Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
Answer:
She is incorrect
Step-by-step explanation:
Pythagorean theorem:
16^2+8^2
256+64=320
320 is 17.89
8^2+8^2
64+64=128
√128 is 11.31
Ada is incorrect. The length of diagonal SQ is bigger than the length of diagonal OM. But it is not two times bigger.
A number is prime if its only divisors are 1 and the number itself.
Out of your numbers, 36 and 38 are even, and thus divisible by 2, so they aren't prime.
Similarly, 35 ends with 5, so it's divisible by 5, and is not prime.
37 is divisible only by 1 and 37, and thus it's prime.
