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shtirl [24]
3 years ago
10

Number of molecules of oxygen produced along with one molecule of sugar

Chemistry
1 answer:
Brums [2.3K]3 years ago
5 0

Answer:

6 molecules of Oxygen

Explanation:

From the question ,

Sugar has a molecular formula of C₆H₁₂O₆ .

Hence ,  

Using the mole concept , i.e. ,  

1 molecule of Sugar , i.e. , C₆H₁₂O₆ has , 6 molecules of Carbon , 12 molecules of Hydrogen and 6 molecules of Oxygen .  

Therefore ,  

6 molecules of Oxygen is present in 1 molecule of sugar , i.e. ,  C₆H₁₂O₆ .

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Answer:

Robert Boyle

Explanation:

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3 years ago
If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K and then I raise the pressu
mixas84 [53]

Answer:

The answer to your question is V2 = 29.6 l

Explanation:

Data

Pressure 1 = P1 = 12 atm

Volume 1 = V1 = 23 l

Temperature 1 = T1 = 200 °K

Pressure 2 = 14 atm

Volume 2 = V2 = =

Temperature 2 = T2 = 300°K

Process

1.- To solve this problem use the Combine gas law.

             P1V1/T1 = P2V2/T2

-Solve for V2

             V2 = P1V1T2 / T1P2

2.- Substitution

             V2 = (12)(23)(300) / (200)(14)

3.- Simplification

             V2 = 82800 / 2800

4.- Result

            V2 = 29.6 l

5 0
3 years ago
Why must a new flu vaccine be manufactured annually?
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7 0
2 years ago
Determine how many millilitres of a 4.25 M HCl solution are needed to react completely with 8.75 g CaCO3?
Helen [10]

Answer:

41 mL

Explanation:

Given data:

Milliliter of HCl required = ?

Molarity of HCl solution = 4.25 M

Mass of CaCO₃ = 8.75 g

Solution:

Chemical equation:

2HCl + CaCO₃      →    CaCl₂ + CO₂ + H₂O

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 8.75 g / 100.1 g/mol

Number of moles = 0.087 g /mol

Now we will compare the moles of  CaCO₃ with HCl.

                      CaCO₃         :          HCl

                          1               :            2

                      0.087           :         2/1×0.087 = 0.174 mol

Volume of HCl:

Molarity = number of moles / volume in L

4.25 M = 0.174 mol / volume in L

Volume in L = 0.174 mol /4.25 M

Volume in L = 0.041 L

Volume in mL:

0.041 L×1000 mL/ 1L

41 mL

8 0
3 years ago
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