Answer: First, here is the balanced reaction: 2C4H10 + 13O2 ===> 8CO2 + 10H2O.
This says for every mole of butane burned 4 moles of CO2 are produced, in other words a 2:1 ratio.
Next, let's determine how many moles of butane are burned. This is obtained by
5.50 g / 58.1 g/mole = 0.0947 moles butane. As CO2 is produced in a 2:1 ratio, the # moles of CO2 produced is 2 x 0.0947 = 0.1894 moles CO2.
Now we need to figure out the volume. This depends on the temperature and pressure of the CO2 which is not given, so we will assume standard conditions: 273 K and 1 atmosphere.
We now use the ideal gas law PV = nRT, or V =nRT/P, where n is the # of moles of CO2, T the absolute temperature, R the gas constant (0.082 L-atm/mole degree), and P the pressure in atmospheres ( 1 atm).
V = 0.1894 x 0.082 x 273.0 / 1 = 4.24 Liters.
Explanation:
Answer:
CH3COOH
Explanation:
CH3COOH has the highest boiling point because it participates in the strongest intermolecular interactions. The -OH group can participate in hydrogen bonding with other -OH groups. Hydrogen bonds are very strong because they are the result of large partial positive charge on the hydrogen and large partial negative charge on the oxygen. When surrounded by other -OH groups, the partial positive charge on the hydrogen can form temporary bonds with the partial negative charge of an oxygen on another molecule. The stronger the intermolecular interactions, the more difficult they are to overcome, thus increasing the boiling point.
The strongest IMF the other molecules participate in are dipole-dipole. These interactions are not as strong as hydrogen bonding.
Explanation:
thank you thank you thank you for the points
B. The third shell would be empty so that the eight electrons in the second level would be outermost after the atom loses one electron.
Answer:
region 2 and region 3
Explanation:
you can tell by the color of the land my friends^^
