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Dmitry [639]
3 years ago
6

How many hydrogen atoms are in 5 molecules of isopropyl alcohol, cmc010-1.jpghmc010-2.jpgo?

Chemistry
1 answer:
shutvik [7]3 years ago
5 0
There are 40 hydrogen atoms in 5 moles of <span>isopropyl alcohol</span><span />
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Roman mixes 12 liters of 8% acid solution with a 20% acid solution, which results in a 16% acid solution. Find the number of lit
inysia [295]
Let the 8% solution be A, the 20% solution be B and the final solution be C.

C = A + B
C = 12 + B

0.16C = 0.08(12) + 0.2(B)
0.16(12 + B) = 0.96 + 0.2B
0.96 = 0.04B
B = 24 Liters

C = 12 + 24
C = 36 Liters
3 0
3 years ago
What is the enthalpy change when 49.4 ml of 0.430 m sulfuric acid reacts with 23.3 ml of 0.309 m potassium hydroxide?
Leni [432]
Potassium hydroxide commonly known as caustic potash is an inorganic compound with a chemical formula KOH which is a strong base that is marketed in several forms. 

H2SO4(aq) + 2KOH(aq) ---> K2SO4(aq) + 2H2O(l) H°= –111.6 kJ/mol

The answer in this question is -0.402 kJ
7 0
4 years ago
How many joules of heat are needed to change 50.0 grams of ice at 0 C to boil at 120.0 C? Show work
Tcecarenko [31]
This can be done in the following way;
1 determining the heat required to convert 0° C ice to 0°C water
 Heat of fusion of water = 334  J/g
Therefore; Heat = 50 g × 334 J/g =  16700 J
2. Determining the heat required to raise the temperature of water from 0° C to 100°C.
Specific heat of water is 4.18 J/g°C
Change in temperature is 100°C
Therefore; Heat = 50 g × 4.18 J/g°C × 100 = 20900 J
3. Determining the heat required to convert 100 ° C water to 100°C vapor
Heat of vaporization of water = 2257 J/g
Heat = Mass of water × heat of vaporization
Heat = 50 g × 2257 = 112850 J
4. Determining the heat required to go from 100° C to 120° vapor
specific heat of vapor = 2.09 J/g°C
Heat = mass × Specific heat of vapor × change in temperature
        = 50 g × 2.09 ×(120-100) = 2090 J

Therefore the total heat required is 
 = 16700 J + 20900 J + 112850 J + 2090 J =  152540 J or 152.54 kJ

6 0
3 years ago
Bonds between carbon and oxygen (c=o) are more polar than bonds between sulfur and oxygen (s=o). nevertheless, sulfur dioxide (s
Harman [31]

Dipole moment can be defined as the product of magnitude of charge and the distance of separation between the charges. A dipole exists when two or more atoms with different electronegativities are bonded together to form a molecule. The resulting unequal sharing of electrons leads to a molecule with a net positive and a net negative end. Hence the molecule is said polar.

Bonds between carbon and oxygen (C=O) are more polar but carbon dioxide (CO2) does not exhibits a dipole moment because CO2 is a linear molecule and the charge is equally distributed amongst the entire molecule. When molecules have an even charge distribution then there is no dipole moment and the molecule is said to be non-polar. CO2 is a linear molecule, so the dipoles are symmetrical and are equal in magnitude but point in opposite directions so they cancel out each other effect and we get net dipole moment zero.

On the other hand sulfur dioxide (SO2) exhibits a dipole moment because unlike CO2 molecule SO2 is not a linear molecule because of the presence of lone pair on Sulfur (S) atom , the geometry of SO2 is bent. This bent orientation of the oxygen's with respect to the sulfur results in the uneven distribution of positive and negative charges between the sulfur atom and the two oxygen atoms in the diagonal-shaped sulfur dioxide molecule. So the dipoles are not equal in magnitude and they do not cancel out and SO2 molecule exhibit a net dipole moment.

NOTE: If the molecule is linear, the dipoles are equal and exactly opposite in direction, so like a perfectly equal tug-of-war, they cancel each other out, and there is no net dipole in the molecule.

CO2 (linear molecule) = The dipoles are equal and exactly opposite in direction. They cancel each other out, and there is no net dipole in the molecule.

SO2 ( bent shape not linear) = Their is an uneven distribution of positive and negative charges between the sulfur atom and the two oxygen atoms. Dipoles are not equal in magnitude and they do not cancel out and SO2 molecule exhibit a net dipole moment.

7 0
3 years ago
What kind of reaction is this?
Papessa [141]
Single displacement (I’m assuming that’s the same as single replacement)
3 0
3 years ago
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