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dangina [55]
3 years ago
14

Use the slope formula to find the slope of the line through the points (2,10) and (10,−8).

Mathematics
2 answers:
ira [324]3 years ago
8 0

Answer:

m=-9/4

Step-by-step explanation:

Hi there!

The formula for the slope (m) calculated from two points is given as (y2-y1)/(x2-x1), where (x1,y1) and (x2,y2) are points

we are given the two points (2,10) and (10,-8)

to avoid any confusion, let's label the values of the points

x1=2

y1=10

x2=10

y2=-8

now substitute into the formula:

m=(-8-10)/(10-2)

subtract

m=(-18)/(8)

simplify (reduce to lowest terms)

<u>m=-9/4 </u>

Hope this helps!

Salsk061 [2.6K]3 years ago
6 0

The slope formula is the changes of two y-values over/to the changes of two x-values.

\large \boxed{m =  \frac{y_2 - y_1}{x_2 - x_1} }

Substitute two given points in the formula to find the slope. The m-term represents the slope from y = mx+b.

\large{m =  \frac{10 - ( - 8)}{2 - 10} } \\  \large{m =  \frac{10 + 8}{ - 8} } \\  \large{ m =  \frac{18} { - 8} \longrightarrow  \frac{9}{ - 4} } \\  \large \boxed{m =  -  \frac{9}{4} }

Answer

  • The slope is -9/4.

Hope this helps and let me know if you have any doubts!

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Scilla [17]

9514 1404 393

Answer:

  B.  50

Step-by-step explanation:

The alternate interior angles at transversal t across parallel lines AB and CD will be congruent.

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  x = 50 . . . . . . . . . . . subtract x+40

The value of x is 50.

_____

<em>Check</em>

2x+40 = 2×50 +40 = 140

x+90 = 50 +90 = 140 . . . . so the obtuse angles are congruent, as they should be

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<em>Additional comment</em>

The lines AB and CD are not shown as being parallel. We have to assume they are, or we cannot work the problem.

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3 years ago
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lbvjy [14]

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Given bi-quadratic equation is:

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Substituting x^2=a, given bi-quadratic equation reduces in the form of following quadratic equation:

a^2 +95a -500=0\\

Let us factorize the above quadratic equation:

a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\

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x \neq \pm \sqrt{-100}\\

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3 0
3 years ago
PLEASE HELP ME!!!!!!
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Answer:

\huge \red{ c_3 = - 1}

Step-by-step explanation:

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6 0
3 years ago
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you can change the -10/2 to a -5 and it will be easier.
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