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Nataly_w [17]
3 years ago
8

Helllllpppppppppppp.

Physics
1 answer:
JulijaS [17]3 years ago
5 0

Answer:

\tau=0.03\ N-m

Explanation:

Given that,

Force acting, F = 6N

The radius of the path, r=10^{-2}\ m

Angle, \theta=30^{\circ}

We need to find the amount of torque acting on the object. The formula for torque is given by :

\tau=Fr\sin\theta\\\\\tau=6\times 10^{-2}\times \sin(30)\\\\\tau=0.03\ N-m

So, the required torque is equal to 0.03 N-m.

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