Question

Helllllpppppppppppp.

Answer 1

Answer:

$\tau=0.03\ N-m$

Explanation:

Given that,

Force acting, F = 6N

The radius of the path, $r=10^{-2}\ m$

Angle, $\theta=30^{\circ}$

We need to find the amount of torque acting on the object. The formula for torque is given by :

$\tau=Fr\sin\theta\\\\\tau=6\times 10^{-2}\times \sin(30)\\\\\tau=0.03\ N-m$

So, the required torque is equal to 0.03 N-m.