Consider the means of the samples shown in the table. Which value is least likely to be the mean of the population from which th
2 answers:
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The complete question in the attached figure
we know that
<span>The measure of the external angle is the semidifference of the arcs that it covers.
so
</span><span>m∠BED =(1/2)*[mAC-mBD]-------> solve for mBD
mBD=mAC-2</span>m∠BED
mBD=80-2*25--------> mBD=30°
the answer is
mBD=30°
we know that
<span>The measure of the external angle is the semidifference of the arcs that it covers.
so
</span><span>m∠BED =(1/2)*[mAC-mBD]-------> solve for mBD
mBD=mAC-2</span>m∠BED
mBD=80-2*25--------> mBD=30°
the answer is
mBD=30°
We have events:
A - <span>customer orders a chicken sandwich
</span>B - <span>customer orders french fries
and probabilities:
so:
</span>
A - <span>customer orders a chicken sandwich
</span>B - <span>customer orders french fries
and probabilities:
so:
</span>