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3 years ago

The aquarium has 198 guppies, angelfish and catfish altogether.

Mathematics

1 answer:

BabaBlast [244]3 years ago

5 0

Answer:

Number of catfish = 28

Step-by-step explanation:

Let the number of catfish = c

Number of angle fish = c + 6

Number of guppies = 4*(c + 6) = 4c + 4*6 = 4c + 24

Total fishes = 198

c + c + 6 + 4c + 24 = 198 {Combine like terms}

c + c +4c + 6 + 24 = 198

6c + 30 = 198 {Subtract 30 from both sides}

6c = 198 - 30

6c = 168

c = 168/6 {Divide both sides by 6}

c = 28

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A sector with an area of \goldE{48\pi,\text{cm}^2}48πcm 2 start color #a75a05, 48, pi, start text, c, m, end text, squared, end

erik [133]

Answer:

3/8 π radians

Step-by-step explanation:

The Area of a sector when then central angle is in radians = 1/2r² θ

Where

θ = central angle = ?

r = 16 cm

Area of the sector = 48πcm²

Hence

Central angle = Area of a sector ÷ (1/2r²)

= 48πcm² ÷ (1/2 × 16²)

= 48πcm² ÷ 128

Central angle = 3/8π radians

Therefore, Central angle = 3/8π radians

7 0

2 years ago

6-^3 ------ 6-^4 A) 6-7 B) 6-1 C) 61 D) 612

Bad White [126]

The answer should be 6 I.e 6^1 as with indices rules you need to subtract the powers (-3-(-4)) which equals 1

5 0

3 years ago

Read 2 more answers

A customer buys bouquets of tulips and bouquets of roses for $.. What is the price of a bouquet of roses?

olchik [2.2K]

Question:

A customer buys bouquets of tulips and bouquets of roses for $40.25. The bouquet contained 17 tulips and cost $18.25. What is the price of a bouquet of roses?

Answer:

$Rose =\$22.00$

Step-by-step explanation:

Given

$Total = \$40.25$

$Tulips = \$18.25$

Required

The cost of a bouquet of roses

Since the customer bought a bouquet each, the formula to use is:

$Total = Tulip + Rose$

Make Rose the subject

$Rose =Total - Tulip$

$Rose =\$40.25 - \$18.25$

$Rose =\$22.00$

A bouquet of rose costs $22.00

7 0

2 years ago

$15,000 is invested at a rate of 8% compounded quarterly. Identify the compound interest function to model the situation. Then f

Rina8888 [55]

Answer:

A = 15000(1.02)^4t ; $33,120.59

7 0

1 year ago

The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10

Rama09 [41]

Answer:

a) $E(X) = 6.45$

b) $E(X^{2} )= 57.25$

c) $V(X) = 15.648$

d) E(3X + 2) = 21.35

e) $E(3X^{2} +2) = 173.75$

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) $E(X) = \sum xP(x)$

$E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45$

$E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\ E(X^{2} )= 57.25$

$V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648$

$E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35$

$E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75$

$V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832$

$E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45$

$V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648$

6 0

3 years ago