The probability that only one shows a 2.
There are 36 different outputs (6x6) = 36
There are 6 combinations where the first cube shows a 2, these are 2,1;2,2;2,3;2,4;2,5; and 2.6
There are 6 combinations where the second cube shows a 2: 1,2;2,2;3,2;4,2;5,2; and 6,2.
Of those one combination on each set shows two 2.
Then the number of combinations with only one 2 are 6 - 1 + 6 -1 = 10
Now the probabilit is 10 out of 36 = 10 / 36 = 5 / 18
m = money earned in one week
h = hours worked
x = times credit card was swiped
m = 14.45h + 8.50x
Step-by-step explanation:
last week there were
62 + 60 + 2 = 124 customers.
that means that the fraction of the customers, who paid by credit card, was
2/124 = 1/62
in situations like that, when we use history data and try to predict future behavior, we use that past experience and extrapolate to a predicted result.
we simply say that we expect the same fraction, 1/62, if customers to use credit cards.
for the absolute number of predicted credit card customers we multiply the predicted number of customers by the expected fraction
1000 × 1/62 = 500/31 = 16.12903226... ≈ 16
so, he expects 16 credit card customers.
