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dusya [7]
3 years ago
10

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
yaroslaw [1]3 years ago
7 0

Answer:

here is your ans

Option A ✅ is correct ✔☑ ...

because when we solve it, we will find 0.1...

Anna11 [10]3 years ago
3 0

Answer:

1

Step-by-step explanation: 0. 1 is a pure repeating bicimal with a repeating cycle of one digit, so the fraction it converts to is 1/1; in other words, 1

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Convert 89/10 into a mixed number ​
kompoz [17]

Answer:

8 9/10

Step-by-step explanation:

89 goes into 10 8 times.

8x10=80.

89-80=9

So the answer is 8 9/10

6 0
3 years ago
Read 2 more answers
How would you change 2x^2=8x-3 into an equation you could solve using the quadratic formula
tatyana61 [14]
0=2x^2=8x+3
hope this helps 
4 0
3 years ago
Which of the following is the equation of a line perpendicular to the line y=-10×+1 passing through the point (5,7)
Juliette [100K]
Y = -10x + 1...slope here is -10. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal of a number, flip the number and change the sign. So our perpendicular line will need a slope of 1/10.

y = mx + b
slope(m) = 1/10
(5,7)....x = 5 and y = 7
now sub and find b, the y int
7 = 1/10(5) + b
7 = 1/2 + b
7 - 1/2 = b
14/2 - 1/2 = b
13/2 = b

so ur perpendicular line going thru (5,7) is y = 1/10x + 13/2
3 0
3 years ago
A rectangular prism has dimensions of 3 cm. by 5 cm. by 5 cm. What is its surface area?
Bogdan [553]

\bf \textit{surface area of a rectangular prism}\\\\ SA=2Lw+2Lh+ 2wh~~ \begin{cases} L=length\\ w=width\\ h=height\\ \cline{1-1} L=3\\ w=5\\ h = 5 \end{cases} \\\\\\ SA=2(3\cdot 5)+2(3\cdot 5)+2(5\cdot 5)\implies SA=30+30+50\implies SA=110

4 0
3 years ago
{ PLEASE ANSWER QUICKLY, PROBLEM DUE ASAP } The functions f(x) and g(x) are defined below. Which expression is equal to f(x) + g
8090 [49]

Answer:

Option C. 2x + 20 / x² + 6x – 40

Step-by-step explanation:

f(x) = x + 16 / x² + 6x – 40

g(x) = 1 / x + 10

To find f(x) + g(x), please refer to the attached photo.

7 0
3 years ago
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