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3 years ago

Product of (6x+8us^2)(x-us^2)

Mathematics

2 answers:

Lerok [7]3 years ago

7 0

Answer:

−8s4u2+2s2ux+6x2

Step-by-step explanation:

=(6x+8us2)(x+−s2u)

=(6x)(x)+(6x)(−s2u)+(8us2)(x)+(8us2)(−s2u)

=6x2−6s2ux+8s2ux−8s4u2

=−8s4u2+2s2ux+6x2

lys-0071 [83]3 years ago

7 0

Answer:

6x² + 2xus² - 8u²s^4

Step-by-step explanation:

(6x+8us²)(x-us²)

6x² - 6xus² + 8xus² - 8u²s^4

6x² + 2xus² - 8u²s^4

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3 years ago

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2 years ago

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The right expression to calculate how much money will be in an investment account 14 years from now if you deposit $5,000 now an

Svet_ta [14]

Answer:

The expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

Step-by-step explanation:

The formula to compute the future value is:

$FV=PV[1+\frac{r}{100}]^{n}$

PV = Present value

r = interest rate

n = number of periods.

It is provided that $5,000 were deposited now and $3,000 deposited after 6 years at 10% compound interest. The amount of time the money is invested for is 14 years.

The expression to compute the amount in the investment account after 14 years is,

$FV=5000[1+\frac{10}{100}]^{14}+3000[1+\frac{10}{100}]^{14-6}\\FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}$

The future value is:

$FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}\\=18987.50+6430.77\\=25418.27$

Thus, the expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

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3 years ago