What is the problem 2x-4y=12 ??

Mike pent $11. 19 on a bag containing red and blue candie. The bag weighed 11 pound. The red candy cot $1. 29 a pound and the bl

Olin [163]

Mike bought 5 pounds of red candy and 6 pounds of blue candy.

What is word problem?

Our comprehensive list of math problems focuses on addition, subtraction, multiplication, division and more specific operations. A math problem is a math question written in one or more sentences that asks a child to apply math knowledge to the "real world." life scenario. This means that children need to be familiar with the vocabulary related to the mathematical symbols they used to understand the meaning of word problems.

Here Mike spent $11.19 on a bag of red and blue candies and both candies weigh 11 lbs

=>Red candies weigh x lbs

=>Blue candies weigh (11-x) lbs

Here cost of x red candy is

=>$1.29/lb* x lbs of red candy

=> 1.29x

Now ,(11-x) lbs of blue candy costs $0.79 (11-x) = $8.69-0 .79 x

Due to the problem, $8.69 - 0.79 x + 1.29 x = $11.19

or $0.50 x = $11.19 - $8.69 = 2.50 $

or $50 x / 100 = $250 / $100

or $50 x = 250 $

or x = 250/50 = 5, red The candy weighs 5 pounds

The blue candy weighs =11-x=11–5=6 pounds

Therefore mike bought 5 pounds of red candy and 6 pounds of blue candy.

To learn more about word problem refer the below link

brainly.com/question/21405634

#SPJ4

8 0

1 year ago

The ratio of the number of text messages sent by Diego to the number of text messages sent by his sister is 3 to 4. Diego sent 1

ipn [44]

Answer:

His sister sent 6 more messages than Diego.

Step-by-step explanation:

Ratio of Diego's messages to his sister's messages = 3 : 4

Text messages sent by Diego = 18

Text messages sent by his sister = x

Ratio = 18 : x

It is a proportional relationship,

3 : 4 :: 18 : x

Product of extremes = Product of means

3x = 18*4

3x = 72

$\frac{3x}{3}=\frac{72}{3}\\x=24$

Difference = 24 - 18 = 6

Therefore,

His sister sent 6 more messages than Diego.

7 0

3 years ago

I’m wondering if you could give me answers

leonid [27]

Answer:

the answer is b bro

Step-by-step explanation:

3 0

3 years ago

A football is kicked toward an end zone with an initial vertical velocity of 30 ft/s. The function h(t) = -16+ 30t models the he

Ulleksa [173]

Answer:

A. The football does not reach a height of 15ft

Step-by-step explanation:

Given

$h(t) = -16t^2 + 30t$

Required

Determine which of the options is true

The option illustrates the height reached by the ball.

To solve this, we make use of maximum of a function

For a function f(x)

Such that:

$f(x) = ax^2 + bx + c$ :

$f(\frac{-b}{2a}) = maximum/minimum$

i.e we first solve for $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for x in $f(x) = ax^2 + bx + c$

In our case:

First we need to solve $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for t in $h(t) = -16t^2 + 30t$

By comparison:

$b = 30$

$c = -16$

$\frac{-b}{2a} = \frac{-30}{2 * -16}$

$\frac{-b}{2a} = \frac{-30}{-32}$

$\frac{-b}{2a} = \frac{30}{32}$

$\frac{-b}{2a} = \frac{15}{16}$

Substitute $\frac{15}{16}$ for t in $h(t) = -16t^2 + 30t$

$h(\frac{15}{16}) = -16(\frac{15}{16})^2 + 30(\frac{15}{16})$

$h(\frac{15}{16}) = -16(\frac{225}{256}) + \frac{450}{16}$

$h(\frac{15}{16}) = -(\frac{225}{16}) + \frac{450}{16}$

$h(\frac{15}{16}) = \frac{-225 + 450}{16}$

$h(\frac{15}{16}) = \frac{225}{16}$

$h(\frac{15}{16}) = 14.0625$

This implies that the maximum height reached is 14.0625ft.

So, the option that answers the question is A because $14.0625 < 15$

8 0

3 years ago

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Artist 52 [7]

cuál de los siguientes documentos es más Útil para construir carretera

3 0

3 years ago