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maria [59]
3 years ago
9

What is the problem 2x-4y=12 ??

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:

(2*8)-(4*1) = 12

Step-by-step explanation:

2*8 = 16

4*1 = 4

16-4 = 12

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\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] ~\dotfill

\stackrel{\textit{"f" varies inversely with "L"}}{f=\cfrac{k}{L}}\qquad \textit{we also know that} \begin{cases} f=\stackrel{lbs}{20}\\ L=\stackrel{ft}{1.5} \end{cases} \\\\\\ 20=\cfrac{k}{1.5}\implies 30=k~\hfill \boxed{f=\cfrac{30}{L}} \\\\\\ \textit{when L = 6, what is "f"?}\qquad f=\cfrac{30}{6}\implies f=5

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3 years ago
What are the solutions of the equation x4 95x2 â€"" 500 = 0? Use factoring to solve.
liq [111]

All the values of the <em>x</em> <em> </em>for the given function are \sqrt{5},-\sqrt{5}, 10i and -10i.

Given-

Given function is,

x^{4}+95x^2-500=0

Rewrite the equation,

(x^2)^2+95x^2-500=0

Let <em>u </em>in place of x^2 and rewrite the equation in the form of u,

u^2+95u-500=0

Break the 95 in factors and rewrite the equation,

u^2+100u-5u-500=0

u(u+100)-5(u+100)=0

(u+100)(u-5)=0

Replace the value of u with x^2,

(x^2+100)(x^2-5)=0

It is known that If any individual factor on the left side of the equation is equal to zero then the entire expression will be equal to zero. therefore we get,

x^2-5=0

further, solve it,

x^2=5

x=\sqrt{5},-\sqrt{5}

And another factor is

x^2+100=0

x^2=-100

x=10i,-10i

Hence, all the values of the <em>x </em>for the given function are \sqrt{5},-\sqrt{5},  10i , and  -10i.

For more about the factorization, follow the link below-

brainly.com/question/6810544

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Please help me ! Find y
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