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3 years ago

Which angle number is adjacent to angle to ZOKL?

Mathematics

1 answer:

Eduardwww [97]3 years ago

4 0

Answer:

there aint no picture

Step-by-step explanation:

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When we multiply the second equation by two, what is the resulting equation?<br><br> 2(5x−2y=8)

Alik [6]

Answer:

10x - 4y = 16

Step-by-step explanation:

2(5x - 2y = 8)

10x - 4y = 16

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3 years ago

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Can someone please help <br> I need a breakdow

Arisa [49]

Answer:

I am so sorry :(

Step-by-step explanation:

I would really love to help you, but i am only in the 6th grade and i do not understand this. Hope someone helps you though :)

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3 years ago

In parallelogram ABCD point K belongs to diagonal

Maksim231197 [3]

Answer:

$\dfrac{BE}{EC}=\dfrac{1}{3}.$

Step-by-step explanation:

Consider triangles BKE and DKA. In this triangles:

$\angle BKE=\angle DKA$ as vertical angles;
$\angle KBE=\angle KDA$ as alternate interior angles (lines BC and AD are parallel and BC is a transversal);
$\angle BEK=\angle DAK$ as alternate interior angles (lines BC and AD are parallel and BE is a transversal).

Thus triangles BKE and DKA are similar by AA theorem. Similar triangles have proportional sides lengths:

$\dfrac{BK}{KD}=\dfrac{BE}{AD}\Rightarrow \dfrac{1}{4}=\dfrac{BE}{AD}.$

Thus, $AD=4BE.$

Since AD=BC and BC=BE+CE, we have that 4BE=BE+EC, EC=3BE. Hence, the ratio BE to EC is

$\dfrac{BE}{EC}=\dfrac{BE}{3BE}=\dfrac{1}{3}.$

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3 years ago

Which expression is equivalent to StartFraction StartRoot 2 EndRoot Over RootIndex 3 StartRoot 2 EndRoot EndFraction?.

miskamm [114]

The expression is equivalent to $\sqrt[6]{2}$ .

<h2>Given that</h2>

Expression; $\dfrac{\sqrt{2}}{\sqrt[3]{2} }$

<h3>We have to determine</h3>

The equivalent expression to the given expression.

<h3>According to the question</h3>

To determine the equivalent relation following all the steps given below.

Expression; $\dfrac{\sqrt{2}}{\sqrt[3]{2} }$

The equivalent expression is;

$= \dfrac{\sqrt{2}}{\sqrt[3]{2} }\\\\= \dfrac{2^{\frac{1}{2}}}{2^{\frac{1}{3}}}\\\\ = 2^{\frac{1}{2}-\frac{1}{3}}\\\\ = 2 ^{\frac{3-2}{6}}\\\\= 2^{\frac{1}{6}}\\\\= \sqrt[6]{2}$

Hence, the expression is equivalent to $\sqrt[6]{2}$ .

To know more about Expression click the link given below.

brainly.com/question/16450385

7 0

2 years ago

Select the pair of equations whose graphs are perpendicular.

viktelen [127]

$k:\ y=m_1x+b_1\ \ \ \ and\ \ \ \ l:\ y=m_2x+b_2\\ \\the\ line\k\ is\ perpendicular\ to\ the\ line\ l\ \ \ \Leftrightarrow\ \ \ m_1\cdot m_2=-1\\----------------------------\\\\A.\\2y=-3x+5\ \ \Rightarrow\ \ \ y=- \frac{3}{2} x+2.5\ \ \Rightarrow\ \ m_1=- \frac{3}{2} \\\\2x+3y=4\ \ \Rightarrow\ \ 3y=-2x+4\ \ \Rightarrow\ \ y=- \frac{2}{3}x+1 \frac{1}{3} \ \ \Rightarrow\ \ m_2=- \frac{2}{3} \\\\m_1\cdot m_2=- \frac{3}{2} \cdot (- \frac{2}{3})=1 \neq -1$

$B.\\5x-8y=9\ \ \Rightarrow\ \ -8y=-5x+9\ \ \Rightarrow\ \ \ y= \frac{5}{8} x-1 \frac{1}{8} \ \Rightarrow\ \ m_1= \frac{5}{8} \\\\12x-5y=7\ \Rightarrow\ \ -5y=-12x+7\ \ \Rightarrow\ \ y= \frac{12}{5}x-1 \frac{2}{5} \ \ \Rightarrow\ \ m_2= \frac{12}{5} \\\\m_1\cdot m_2= \frac{5}{8} \cdot \frac{12}{5}= \frac{3}{2} \neq -1$

$C.\\y=2x-7\ \ \Rightarrow\ \ m_1=2 \\\\x+2y=3\ \Rightarrow\ \ 2y=-x+3\ \ \Rightarrow\ \ y= -\frac{1}{2}x+1 \frac{1}{2}\ \ \Rightarrow\ \ m_2=- \frac{1}{2} \\\\m_1\cdot m_2= 2 \cdot (- \frac{1}{2})= -1\ \ \Rightarrow\ \ y=2x-7\ \ \ \ \perp\ \ \ \ x+2y=3$

$
D.\\x+6y=8\ \ \Rightarrow\ \ 6y=-x+8\ \ \Rightarrow\ \ \ y=- \frac{1}{6} x+1 \frac{1}{3}\ \ \Rightarrow\ \ m_1= -\frac{1}{6} \\\\y=2x-8\ \Rightarrow\ \ m_2= 2 \\\\m_1\cdot m_2= -\frac{1}{6} \cdot2=- \frac{1}{3} \neq -1$

7 0

3 years ago

Which angle number is adjacent to angle to ZOKL? ​

Which angle number is adjacent to angle to ZOKL?