First put a bubble around 5x-7. Now you plug that into the problem. -3x-2
(5x-7)=12. now times the -2 by 5x which is -10x. and then times the -2 by -7 which is 14. so now you have -3x-10x+14=-12. add the -3x and -10x. -13x. Add the 14 over. -13x=2. Now dived by -13, which gives us x=-0.15
Now you take that a plug it into the -3x-2y=-12. So that it looks like this -3(-0.15)-2y=-12
Now times the -3 by -0.15 to give us 20 -2y=-12. Now 'kill' the 20, so that it looks like this -2y=-32. Now you divide by -2 and get y=16.
Now your ordered pair is (-0.15,16)
11. It is not the multiple of any numbers smaller than it
Answer:
72
Step-by-step explanation:
Answer:
24.6967 meters
Step-by-step explanation:
The roots of the tree go 6 and 5 over 12 meters below the ground level.
Now, 6 and 5 over 12 meters is equivalent to 6.4167 meters.
Again the top of the tree is 18.28 meters high from the ground level.
Therefore, the total height of the tree from the bottom of the root to the top is
(6.4167 +18.28) = 24.6967 meters (Answer)
Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.
If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:
E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]
Or, if you're given the expectation and variance of <em>X</em>, you have
Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²
→ E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]
Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.
