There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every
2 answers:
<span>1. In how many games does a girl play against a boy?
A: Because there are 5 girls, each will play against 5 boys, so in total is 5*5 = 25 times.
2. </span><span>In how many games does a girl play against another girl?
A: In this case, we only need to calculate how many girl pairs are there among these 5 girls, and it become a combination problem which can solved by </span>
3.The fraction of games "B vs B" should be the number of "B vs B" (which is 10) divide the total number of the games "B vs B" & "G vs G" & "B vs G" (which is 10+10+25=45, see the analysis in 1.A and 2.A), so the fraction should be 10/45=2/9
4.One person will have to play against 9 people at the tournament, and the total number of the games is 45, so the fraction should be 9/45 = 1/5
A: Because there are 5 girls, each will play against 5 boys, so in total is 5*5 = 25 times.
2. </span><span>In how many games does a girl play against another girl?
A: In this case, we only need to calculate how many girl pairs are there among these 5 girls, and it become a combination problem which can solved by </span>
3.The fraction of games "B vs B" should be the number of "B vs B" (which is 10) divide the total number of the games "B vs B" & "G vs G" & "B vs G" (which is 10+10+25=45, see the analysis in 1.A and 2.A), so the fraction should be 10/45=2/9
4.One person will have to play against 9 people at the tournament, and the total number of the games is 45, so the fraction should be 9/45 = 1/5
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Answer:
The expected participation rate is 0.637.
The standard error is 0.04397
Step-by-step explanation:
For each working age people asked, there are only two possible outcomes. Either they are in the labor force, or they are not. This means that we can solve this problem using binomial distribution probability concepts.
Binomial probability:
Expected value for the participation rate: The expected value is the probability of a success. In this problem, a success is a working age people being in the labor force. 63.7% of them are. So . This means that the expected participation rate is 0.637.
Standard error for the participation rate:
The standard error is given by the following formula:
.
In this problem, 120 people are asked, so
.
So the standard error is 0.04397
Answer:
Step-by-step explanation:
Expand the brackets.
Add -9x and 5x
Add 4x and 6x on both sides.
Add the like terms.
Divide 12 into both sides.