There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every
2 answers:
<span>1. In how many games does a girl play against a boy?
A: Because there are 5 girls, each will play against 5 boys, so in total is 5*5 = 25 times.
2. </span><span>In how many games does a girl play against another girl?
A: In this case, we only need to calculate how many girl pairs are there among these 5 girls, and it become a combination problem which can solved by </span>
3.The fraction of games "B vs B" should be the number of "B vs B" (which is 10) divide the total number of the games "B vs B" & "G vs G" & "B vs G" (which is 10+10+25=45, see the analysis in 1.A and 2.A), so the fraction should be 10/45=2/9
4.One person will have to play against 9 people at the tournament, and the total number of the games is 45, so the fraction should be 9/45 = 1/5
A: Because there are 5 girls, each will play against 5 boys, so in total is 5*5 = 25 times.
2. </span><span>In how many games does a girl play against another girl?
A: In this case, we only need to calculate how many girl pairs are there among these 5 girls, and it become a combination problem which can solved by </span>
3.The fraction of games "B vs B" should be the number of "B vs B" (which is 10) divide the total number of the games "B vs B" & "G vs G" & "B vs G" (which is 10+10+25=45, see the analysis in 1.A and 2.A), so the fraction should be 10/45=2/9
4.One person will have to play against 9 people at the tournament, and the total number of the games is 45, so the fraction should be 9/45 = 1/5
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Answer:
x ≈ 37.53
Step-by-step explanation:
To find the value of x, we will follow the steps below:
first, we need to find angle z
z+47° +90° = 180° (sum of interior angle of a triangle)
z + 137° = 180°
subtract 137° from both-side of the equation
Z + 137°-137° = 180° - 137°
Z=43°
angle Z = 43°
We can now use the sine rule to find the value of x
Using the sine rule
where Z and X are angles and z and x are side length
from the diagram given,
X = 47° and we find Z to be 43°
side z = 35
we can now proceed to substitute the values into the formula
=
cross-multiply
x sin 43° = 35 sin 47°
divide both-side of the equation by sin 43°
x sin 43° /sin 43°= 35 sin 47° /sin 43°
x ≈ 37.53 to two decimal place