Answer
Step-by-step explanation:
There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every
2 answers:
<span>1. In how many games does a girl play against a boy?
A: Because there are 5 girls, each will play against 5 boys, so in total is 5*5 = 25 times.
2. </span><span>In how many games does a girl play against another girl?
A: In this case, we only need to calculate how many girl pairs are there among these 5 girls, and it become a combination problem which can solved by </span>
3.The fraction of games "B vs B" should be the number of "B vs B" (which is 10) divide the total number of the games "B vs B" & "G vs G" & "B vs G" (which is 10+10+25=45, see the analysis in 1.A and 2.A), so the fraction should be 10/45=2/9
4.One person will have to play against 9 people at the tournament, and the total number of the games is 45, so the fraction should be 9/45 = 1/5
A: Because there are 5 girls, each will play against 5 boys, so in total is 5*5 = 25 times.
2. </span><span>In how many games does a girl play against another girl?
A: In this case, we only need to calculate how many girl pairs are there among these 5 girls, and it become a combination problem which can solved by </span>
3.The fraction of games "B vs B" should be the number of "B vs B" (which is 10) divide the total number of the games "B vs B" & "G vs G" & "B vs G" (which is 10+10+25=45, see the analysis in 1.A and 2.A), so the fraction should be 10/45=2/9
4.One person will have to play against 9 people at the tournament, and the total number of the games is 45, so the fraction should be 9/45 = 1/5
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Answer: 26 cm × 4 cm or
36 cm × 2.89 cm
Step-by-step explanation:
The diagram of the board is shown in the attached photo
Width of the rectangular board is given as 26 cm
The length of a rectangular board is 10 cm longer than its with. This means that
Length of rectangular board = 26 +10 = 36 cm.
Area of rectangular board = length × width. It becomes
36 × 26 = 936cm^2
The board is cut into 9 equal pieces. This means that the area of each piece would be the area of the board divided by 9. It becomes
936 /9 = 104cm^2
The dimensions of the piece would be
Since area of each piece is 104 cm^2 and the width of the bigger board still corresponds to one side of each piece, the other side of each piece will be 104 /26 = 4 cm
Also, the board could have been cut along the length such that one side of the cut piece corresponds to the length of the original board (36 cm)
and the other side becomes
104 /36 = 2.89 cm
The possible dimensions are
26 cm × 4 cm or
36 cm × 2.89 cm
