Evaluate the limit. lim n > [infinity] 9n^3 +5n - 2n/ 2n^3

Mathematics

1 answer:

expeople1 [14]3 years ago

7 0

Answer:

The value of the limit is $\frac{9}{2}$

Step-by-step explanation:

When we are working with limits in which the variable goes to infinity, we only take the highest order factor of the numerator and of the denominator.

So we have

$\lim_{t \to +\infty} \frac{9n^{3}}{2n^{3}}$

We can simplify the cubes.

$\lim_{t \to +\infty} \frac{9}{2}$

The limit of a constant is the proper constant.

So the value of the limit is $\frac{9}{2}$

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Step-by-step explanation:

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= $\sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})$

= $6_{C_{0}} \times x^{0} \times 2^{6} + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4}$ + terms involving higher powers of x