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Zinaida [17]
3 years ago
11

Evaluate the limit. lim n > [infinity] 9n^3 +5n - 2n/ 2n^3

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

The value of the limit is \frac{9}{2}

Step-by-step explanation:

When we are working with limits in which the variable goes to infinity, we only take the highest order factor of the numerator and of the denominator.

So we have

$\lim_{t \to +\infty} \frac{9n^{3}}{2n^{3}}$

We can simplify the cubes.

$\lim_{t \to +\infty} \frac{9}{2}$

The limit of a constant is the proper constant.

So the value of the limit is \frac{9}{2}

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