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Zinaida [17]
3 years ago
11

Evaluate the limit. lim n > [infinity] 9n^3 +5n - 2n/ 2n^3

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

The value of the limit is \frac{9}{2}

Step-by-step explanation:

When we are working with limits in which the variable goes to infinity, we only take the highest order factor of the numerator and of the denominator.

So we have

$\lim_{t \to +\infty} \frac{9n^{3}}{2n^{3}}$

We can simplify the cubes.

$\lim_{t \to +\infty} \frac{9}{2}$

The limit of a constant is the proper constant.

So the value of the limit is \frac{9}{2}

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If the circumference of a circle is x, then what is the area of the circle in terms of x?
grandymaker [24]

Answer:

x^2 / 4pi

Step-by-step explanation:

The area of a circle is (pi x r)^2

The circumference of a circle is 2pi x r

The find the radius, you need to divide x by 2pi, so x / 2pi

Then just plug it in as the radius:

(pi x (x / 2pi))^2 = x^2 / 4pi

7 0
3 years ago
Help ASAP-----------------
lilavasa [31]

Answer:

18

Step-by-step explanation:  

subtract 32 and 14

6 0
3 years ago
Round 149,640 to the nearest thousand.
love history [14]
150,000 I believe is the answer
6 0
3 years ago
Read 2 more answers
A region with a 5-mile radius has a population density of about 3100 people per square mile. Find the number of people who live
Gwar [14]

Answer:

243,000 people

Step-by-step explanation:

First, what we need to do is to calculate the area of the region using the 5-mile radius

Mathematically, we can calculate this as the area of a circle

Area = pi * r^2

Our r here is 5 miles

Area = pi * 5^2 = pi * 25 = 78.54 square miles

Now to get the population, we know that per square mile we have 3,100.

Hence per 78.54 square mile, we have 78.54 * 3100 = 243,273 people

To the nearest thousand, 243,000

4 0
3 years ago
3(q-7)=273(q−7)=27 find q
skelet666 [1.2K]

Answer:

q = 16

Step-by-step explanation:

3(q - 7) = 27

3q - 21 = 27

3q = 27 + 21

3q = 48

q = 48/3

q = 16

5 0
3 years ago
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