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Gekata [30.6K]
3 years ago
7

Y is inversely proportional to the square of x. If Y = 3 when x = 3, then Y =

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
4 0

Answer:

It will be same the value of second Y

ivanzaharov [21]3 years ago
4 0

Answer:

y = \frac{27}{x^2}

Step-by-step explanation:

Assuming you require the equation of proportion.

Given y is inversely proportional to x² , then the equation relating them is

y = \frac{k}{x^2}

To find k use the condition if y = 3, then x = 3, that is

3 = \frac{k}{3^2} = \frac{k}{9} ( multiply both sides by 9 )

27 = k

y = \frac{27}{x^2} ← equation of proportion

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kvasek [131]
Yeah I just took the text it’s false
3 0
3 years ago
How do you solve 8 / 1/4
Ber [7]
8/  \frac{1}{4}

8*4

32
3 0
3 years ago
I need help answering this question!! Why does the equation (x-4)^2 – 28 = 8 have two solutions?
andre [41]

Answer:

For your first answer it is because they are two different ways to solve the equation

Step-by-step explanation:

For Example!

<h2>Solution 1:</h2>

(x-4)² – 28 = 8

The 8 is positive making it a different equation (this is like absolute value). (I am assuming you know the answer to the probelm)

<h2>Solution 2:</h2>

(x-4)² – 28 = -8

The 8 could be negative meaning that when you add the 28 to the right side it is -8+28 which will be a negative!

<h3>I hope this helps</h3><h2>IF IT DOES HELP PLEASE GIVE IT A BRAINLIEST!</h2>
5 0
2 years ago
What is the end behavior? 10 points!!
Colt1911 [192]

Given:

The given function is:

f_1(x)=-3\cdot 2^{x-5}-4

The graph of the function is given.

To find:

The end behavior of the given function.

Solution:

We have,

f_1(x)=-3\cdot 2^{x-5}-4

From the given graph it is clear that the function approaches to -4 at x approaches negative infinite and the function approaches to negative infinite at x approaches infinite.

f_1(x)\to -4 as x\to -\infty

f_1(x)\to -\infty as x\to \infty

Therefore, the end behaviors of the given function are:

f_1(x)\to -4 as x\to -\infty

f_1(x)\to -\infty as x\to \infty

4 0
3 years ago
A. The point-slope form of the equation of a line is y ? y1 = m(x ? x1), where m is the slope and (x1, y1) is a point on the lin
Rudiy27

Answer:

A.

y - 5 = -2(x-6)

Negative reciprocal gives you the perpendicular slope so negative reciprocal of 1/2 is -2.

Then apply point-slope form.

B. The answer is x = 6.

The midpoint of JK is

\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{8+ 4}{2}, \frac{4 + 4}{2} \right) = \left(6,4\right)

The line that goes through JK is just a horizontal line y = 4 because the y-coordinate does not change. So its perpendicular bisector is the vertical line that goes through the x-coordinate of the midpoint, that is, x = 6.

8 0
3 years ago
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