Answer:
We can create a one-variable equation and solve for x.
we set 35.25+0.11x equal to 14.25+0.32x
35.25+0.11x=14.25+0.32x
then we just solve for x to get 100
Step-by-step explanation:
The effective annual yield is 3.04%
What is effective annual yield?
Effective annual yield is the rate of return that considers the frequency of compounding, in other words, the number of times in a year that interest on the balance is compounded.
The easiest way to determine the effective annual yield in this case is to compare the end of the year balance with the initial balance at the start of the year
effective annual yield=(ending balance/initial balance)-1
ending balance=$4,121.66
initial balance=$4000
effective annual yield=($4,121.66/$4000)-1
effective annual yield=3.04%
Another way to determine the effective annual yield is use the below formula which considers that interest rate is 3% compounded monthly, in other words, n, the frequency of compounding is 12
EAR=(1+r/n)^n-1
r=3%
n=12
EAR=(1+3%/12)^12-1
EAR=3.04%
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(a) Without solving the equation we can't determine whether its true or false.
(b) If x = 3
4x + 1 = 2x + 5
4(3) + 1 = 2(3) + 5
12 + 1 = 15 + 5
13 = 20
No, if x = 3, the equation will not be true.
(c) 4x + 1 = 2x + 5
4x - 2x = 5 - 1
2x = 4
x = 4/2
x = 2
This shows that x = 2 makes the equation true.
Answer:
Standard deviation of the weight over a day is 1.15
Step-by-step explanation:
Since it is given that water weight is uniformly distributed between -2 to 2.
So applying formula for variance of uniformly distribution as follows,

From the given data, values of a and b is ,
,
..
Substituting the values,

Now, 



Dividing the fraction by 4,

So, the value of variance is 
The formula for standard deviation is given as,

Substituting the value,


Rounding to 2 decimal places,

So, the value of standard deviation is 1.15.
Answer:
D. Sarah does not have convincing statistical evidence to conclude that the population mean number of days for the plants to produce fruit is different from 87 days.
Step-by-step explanation:
The population mean, μ is given as 87
This population value is used to state the Null hypothesis ;
H0 : μ = 87
The alternative hypothesis is the opposite of the Null ; and hence, claims that the mean is different from the population mean, μ ≠ 87
H1: μ ≠ 87
The Decison level :
When Pvalue < α ; We reject the Null otherwise we fail to reject the null
The given p and α value :
P-value = 0.0752
α = 0.05
0.075 > 0.05 ; Hence ;
Pvalue > α ; We fail to reject the Null
We can thus conclude that there is not enough evidence to conclude that the population mean number of days for the plants to produce fruit is different from 87 days.