Answer:
Part a)
Part b)
Explanation:
Part a)
As we know that proton is accelerated uniformly so we can use kinematics here to find the final speed
so we know that
so we will have
Part b)
Now increase in kinetic energy is given as
![\Delta K = \frac{1}{2}(1.67 \times 10^{-27})[(2.569 \times 10^7)^2 - (2.4 \times 10^7)^2]](https://tex.z-dn.net/?f=%5CDelta%20K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%281.67%20%5Ctimes%2010%5E%7B-27%7D%29%5B%282.569%20%5Ctimes%2010%5E7%29%5E2%20-%20%282.4%20%5Ctimes%2010%5E7%29%5E2%5D)
The only thing you can derive ...maybe ... from the given information is that
the stroller's x(t) is 1 + the mother's x(t). And if her progress is not strictly
along the x-axis, then even <em>that</em> statement isn't true.
If the stroller's v(t) and a(t) were not identical to the mother's v(t)and a(t), then
mother and stroller would "come apart". But you've told us that they're always
in contact, so their v(t) and a(t) must be identical.
A slightly more rigorous (and mathematical) argument is that since the mother's
and the stroller's x(t) differ (at most) only by a constant, then their derivatives
x'(t) (which is v(t)) and x''(t) (which is a(t)) are equal.
The three main types of stress go along with the three types of plate boundaries: compression is common at convergent boundaries, tension at divergent boundaries, and shear at transform boundaries. Hope this helps
