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3 years ago

A car has a mass of 1500. It is traveling north a 8 m/s. What is the cars momentum

Physics

1 answer:

Mama L [17]3 years ago

7 0

Momentum = mass x velocity
= 1500 x 8
= 12000 kg m/s

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If you want the ball to land in your hand when it comes back down, should you toss the ball straight upward, in a forward direct

denpristay [2]

Straight upward

the ball moves in the forward direction with your walking speed at all times. If you want the ball to land in your hand when it comes back down, you should toss the ball straight upward.

<h3>What is Projectile motion ?</h3>

Projectile motion is the motion of an object thrown (projected) into the air.

After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory

A projectile can be a thrown ball, a bullet or a springboard diver ... Except for air resistance, the forward velocity of any projectile is constant and is equal to the initial velocity when it was released.

Learn more about Projectile motion here:

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2 years ago

3. Forces do ________ always cause an object to move.<br> need this ASAP

Finger [1]

Answer:

not

Explanation:

5 0

3 years ago

Read 2 more answers

Hich of the following equations is balanced correctly?

Alexus [3.1K]

A. the carbons are unbalanced B. the hydrogens are unbalanced. D. the chlorines are unbalanced. That leaves C. to be correctly balanced.

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4 years ago

A uniform-density 7 kg disk of radius 0.21 m is mounted on a nearly frictionless axle. Initially it is not spinning. A string is

GREYUIT [131]

Answer:

$\omega = 22.67 rad/s$

Explanation:

Here we can use energy conservation

As per energy conservation conditions we know that work done by external source is converted into kinetic energy of the disc

Now we have

$W = \frac{1}{2}I\omega^2$

now we know that work done is product of force and displacement

so here we have

$W = F.d$

$W = (44 N)(0.9 m) = 39.6 J$

now for moment of inertia of the disc we will have

$I = \frac{1}{2}mR^2$

$I = \frac{1}{2}(7 kg)(0.21^2)$

$I = 0.154 kg m^2$

now from above equation we will have

$39.6 = \frac{1}{2}(0.154)\omega^2$

$\omega = 22.67 rad/s$

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3 years ago

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Problem: Hooke's law states that the force on a spring varies directly with the distance that it is stretched. If a spring has a

Scorpion4ik [409]

Answer:

Restoring force of the spring is 50 N.

Explanation:

Given that,

Spring constant of the spring, k = 100 N/m

Stretching in the spring, x = 0.5 m

We need to find the restoring force of the spring. It can be calculated using Hooke's law as "the force on a spring varies directly with the distance that it is stretched".

$F=kx$

$F=100\ N/m\times 0.5\ m$

F = 50 N

So, the restoring force of the spring is 50 N. Hence, this is the required solution.

7 0

4 years ago