Given a complex number in the form:
The nth-power of this number,
, can be calculated as follows:
- the modulus of
is equal to the nth-power of the modulus of z, while the angle of
is equal to n multiplied the angle of z, so:
In our case, n=3, so
is equal to
(1)
And since
and both sine and cosine are periodic in
, (1) becomes
Answer:
6t+4
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
you multiply each dot by the fraction of hours it is under. you add everything up and you should get 66/8 which is equivalent to 8 and 1/4