Answer:
133
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
f(1)=7(1-1)+8
f(1)=7(0)+8
f(1)=0+8
f(1)=8
The formula is (x-h)^2+(y-k)^2=r^2
so, using this, and knowing that h is -3 and k is -5 and r is 4, we get
(x--3)^2+(y--5)^2=(4)^2, which equals
(X+3)^2+(y+5)^2=16
:)
Let the number of hours = x
Mine A is offering his services for an initial $90 in addition to $15 per hour.
So, Charges of A = 90 + 15x
Mine B is offering her services for an initial $30 in addition to $35 per hour.
so, Charges of B = 30 + 35x
The two mines charge the same amount of money when:
Charges of A = Charges of B
So,
![90+15x=30+35x](https://tex.z-dn.net/?f=90%2B15x%3D30%2B35x)
solve for x
combine like terms
![\begin{gathered} 35x-15x=90-30 \\ 20x=60 \\ x=\frac{60}{20} \\ \\ x=3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2035x-15x%3D90-30%20%5C%5C%2020x%3D60%20%5C%5C%20x%3D%5Cfrac%7B60%7D%7B20%7D%20%5C%5C%20%20%5C%5C%20x%3D3%20%5Cend%7Bgathered%7D)
so, the two mines will charge the same amount of money when the number of hours = 3