![y=\dfrac{p}{q+x}\\\\\dfrac{1}{y}=\dfrac{1}{\frac{p}{q+x}}=\dfrac{q+x}{p}](https://tex.z-dn.net/?f=%20y%3D%5Cdfrac%7Bp%7D%7Bq%2Bx%7D%5C%5C%5C%5C%5Cdfrac%7B1%7D%7By%7D%3D%5Cdfrac%7B1%7D%7B%5Cfrac%7Bp%7D%7Bq%2Bx%7D%7D%3D%5Cdfrac%7Bq%2Bx%7D%7Bp%7D%20)
We have x and y intercept:
(2, 0) and (0, 3).
Substitute the coordinates of points to the equation:
![(2,\ 0)\\\\0=\dfrac{q+2}{p}\to q+2=0\to q=-2\\\\(0,\ 3)\\3=\dfrac{q+0}{p}\to3p=q\to3p=-2\to p=-\dfrac{2}{3}](https://tex.z-dn.net/?f=%20%282%2C%5C%200%29%5C%5C%5C%5C0%3D%5Cdfrac%7Bq%2B2%7D%7Bp%7D%5Cto%20q%2B2%3D0%5Cto%20q%3D-2%5C%5C%5C%5C%280%2C%5C%203%29%5C%5C3%3D%5Cdfrac%7Bq%2B0%7D%7Bp%7D%5Cto3p%3Dq%5Cto3p%3D-2%5Cto%20p%3D-%5Cdfrac%7B2%7D%7B3%7D%20)
No solution because you can’t even out both sides
It would be .10 bc they are both decimals
Answer:
x = 11
Step-by-step explanation:
The relationship between the sine and cosine functions can be written as ...
sin(x) = cos(90 -x)
sin(A) = cos(90 -A) = cos(B) . . . . substituting the given values
Equating arguments of the cosine function, we have ...
90 -(3x+4) = 8x -35
86 -3x = 8x -35
86 +35 = 8x +3x . . . . . add 3x+35 to both sides
121 = 11x . . . . . . . . . . . . collect terms
121/11 = x = 11 . . . . . . . . divide by 11
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<em>Comment on the solution</em>
There are other applicable relationships between sine and cosine as well. The result is that there are many solutions to this equation. One set is ...
11 +(32 8/11)k . . . for any integer k
Another set is ...
61.8 +72k . . . . . for any integer k
Answer:
$8.40
Step-by-step explanation:
to find discount you use part=%(whole) so you are looking for your part but know the % and whole so you do x=40%(21) and 40%, or 0.4, times 21 is 8.4 so thats your part, 8.4 is 40% of 21 and thats how much youll pay