5x+2y=-10 -3x - 2y=6 Solve by elimination I’m confused

√-225 • √-36 . show work.

Darya [45]

Answer:

±90

Step-by-step explanation:

√(-225) · √(-36) = (15i)·(6i) = 90i² = 90·(-1) = -90

_____

On the other hand, ...

... √(-225) · √(-36) = √((-225)·(-36)) = √8100 = 90

___

If you consider all the roots at each stage, the result is ±90. Since you're working with complex numbers here, it is reasonable to recognize every number has two square roots.

... √(-225) = ±15i

... √(-36) = ±6i

... √(-225) · √(-36) = (±15i)·(±6i) = ±90i² = ±90

7 0

3 years ago

Please help I'm doing homework and its due at 1:00!

olga55 [171]

Your answer is correct it’s 4/33. You first have to convert the mixed number into an improper fraction. Then you’ll have 1/6/11/8 and then you will simplify the complex fraction. I hope that helps!

4 0

2 years ago

Q # 4 anybody help me please

Marysya12 [62]

Answer

-5/3, -1, 0.7, √2, √5

Explanation

√5 = 2.236

-1 ⇒ this is less than 1.

-5/3 = -1.666667 this is less than 1. -5/3 < -1

0.7 > -1

√2 = 1.414 ⇒ √5 > √2

Arranging them from the least to the greatest;

-5/3, -1, 0.7, √2, √5

8 0

2 years ago

Eliminate the double signs in the expression -18-(+1)+(+16)+(-2)

Savatey [412]

Answer:

-5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

3 years ago