Answer:
The nonpolar tails in the middle of the plasma membrane
Explanation:
Answer:
1. Acetylcholine binds to receptors on the motor end plate
2. Ligand-gated channels open leading to depolarization
3. End plate potential triggers an action potential
4. Transverse tubules convey action potentials into the interior of the muscle fiber
5. Calcium is released from the sarcoplasmic reticulum
6. Calcium ions bind to troponin, which then moves tropomyosin
Explanation:
Acetylcholine (ACh) is a signaling molecule (neurotransmitter) that binds to receptors on muscle cells. This binding triggers the opening of ligand-gated sodium channels, thereby ions enter into muscle cells, which causes the depolarization of the sarcolemma and thus promotes the release of Ca2+ ions from the sarcoplasmic reticulum. The myoneural junction, also known as the motor endplate, is the site of synaptic contact between a motor axon and a skeletal muscle fiber. The endplate potential is the voltage that produces the depolarization of muscle fibers when ACh molecules bind to their receptors in the cell membrane. This depolarization spreads in the sarcolemma through transverse tubules (T tubules) and thus generates an action potential. Finally, this action potential induces the release of Ca2+ in the sarcoplasmic reticulum, which activates troponin protein and induces muscle contraction.
Answer: True
Explanation: Ion channels are very specific and are voltage gated channels. They are highly specific and selective for particular ions only.
Example: Some of the channels allow the flow of potassium ions but do not allow sodium ions to cross the membrane to maintain the concentration.
Some of the positive ion channels allow only the movement of positive ions and no negative ions. These channels are not always open and opens only when there is a concentration gradient.
Answer: I would say 3/16 but then again im not too sure you may want to wait until a second answer arrives :D
