In this relation we have two ordered pairs:
( 5, 7 ) and ( 5, 8 )
For x = 5 : f ( x ) = 7 and also for x = 5, f ( x ) = 8. This is not possible for a function.
Answer:
b ) No. The relation is not a function.
Try and do the Pythagorean theorem a^2 + b^2= c^2
Answer:
The correct answer is letter A.
Step-by-step explanation:
Well it depends on what you're working with if it's a large or smaller number of choice.
