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ASHA 777 [7]
3 years ago
9

√12 + √10 − √2) is

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0

Hello!

\bf  \sqrt{12}  + \sqrt{10}  -  \sqrt{2} =

\bf  \sqrt{ {2}^{2}  \times 3}  +  \sqrt{10}  -  \sqrt{2}  =

\bf  \sqrt{ {2}^{2} }  \sqrt{ 3}  +  \sqrt{10}  -  \sqrt{2}  =

\bf \boxed{ 2  \sqrt{3}  +  \sqrt{10}  -  \sqrt{2}}

Answer: (c) An irrational number

Good luck! :)

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Q(3x)=12x+2 then what is Q(x-2)
Mandarinka [93]

Answer:

it's ax+b form answer is Q(x-2)=4x-6

Step-by-step explanation:

ax+b=Q(x),Q(x-2)=a(x-2)+2

Q(3x)=a(3x)+b=12x+2, 3a=12 =>a=4,b=2

the original q of x is 4x+2

Q of x-2 =4(x-2)+2=4x-8+2=4x-6

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2 years ago
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3 years ago
Work out the volume of the shape​
pashok25 [27]

Answer:

\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}

Step-by-step explanation:

We have the cone and the half-sphere.

The formula of a volume of a cone:

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r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3

The formula of a volume of a sphere:

V_s=\dfrac{4}{3}\pi R^3

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Therefore the formula of a volume of a half-sphere:

V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3

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V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3

The volume of the given shape:

V=V_c+V_{hs}

Substitute:

V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3

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