Chapter : Algebra
Study : Math in Junior high school
x = 7 + √40
find √x of √x + 1
= √x + 1
= √(7+√40) + 1
in Formula is :
= √7+√40 = √x + √y
= (√7+√40)² = (√x + √y)²
= 7+√40 = x + 2√xy + y
= 7 + √40 = x + y + 2√xy
→ 7 = x + y → y = 7 - x ... Equation 1
→ √40 = 2√xy → √40 = 2.2√10 = 4√10
= xy = 10 ... Equation 2
substitution Equation 1 to 2 :
= xy = 10
= x(7-x) = 10
= 7x - x² = 10
= x² - 7x + 10 = 0
= (x - 5)(x - 2) = 0
= x = 5 or x = 2
Subsitution x = 5 and x = 2, to equation 1
#For x = 5
= y = 7 - x
= y = 7 - (5)
= y = 2
#For x = 2
= y = 7 - x
= y = 7 - (2)
= y = 5
and his x and y was find :
#Equation 1 :
= x = 5 and y = 2
#Equation 2 :
= x = 2 and y = 5
So that :
√7+√40 = √x + √y
= √7+√40 = √2 + √5
And that is answer of question :
= √2 + √5 + 1
7x - 2y = -3
14x + y = 14
14x -14x + y = 14-14x
Y = 14 - 14x
7x -2y = -3
7x - 2(14 - 14x) = -3
7x -28 + 28x = -3
7x + 28x - 28 = -3
35x - 28 = -3
35x - 28 + 28 = -3 + 28
35x = 25
35x/35 = 25/35
X = 25/35 = 5/7.
Y = 14 - 14x
Y = 14 - 14(5/7)
Y = 14 - 10
Y = 4.
The solution P(5/7,4).
The first box is -7 and the other one is just 7
180-48.2-75=56.8 thank you
