You want to try and get rid of one of the variables ( x or y) so you would multiply the second equation by 2 which would make the x variable -2x which then when added to the first equation would eliminate the x variable.
Answer: c. Multiply the second equation by 2.
You can solve an easy equation in your head by using the multiplication table.
Answer:
and
.
Step-by-step explanation:
If we have to different functions like the ones attached, one is a parabolic function and the other is a radical function. To know where
, we just have to equalize them and find the solution for that equation:

So, applying the zero product property, we have:
![x=0\\x^{3}-1=0\\x^{3}=1\\x=\sqrt[3]{1}=1](https://tex.z-dn.net/?f=x%3D0%5C%5Cx%5E%7B3%7D-1%3D0%5C%5Cx%5E%7B3%7D%3D1%5C%5Cx%3D%5Csqrt%5B3%5D%7B1%7D%3D1)
Therefore, these two solutions mean that there are two points where both functions are equal, that is, when
and
.
So, the input values are
and
.
Answer:
(2, - 9 )
Step-by-step explanation:
Since 2 is the output when - 9 is input to f(x)
Then reversing the procedure, that is the inverse gives an output of - 9 for an input of 2.
(- 9, 2) is a point on the graph of f(x), then
(2, - 9) is a point on the graph o the inverse function
(x)