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3 years ago

I need the answer asap!!

Mathematics

1 answer:

slamgirl [31]3 years ago

4 0

Answer:

Step-by-step explanation:

x² × 2x² = 2x^4 (2x to the power of 4)

x² × -3x = -3x³

+3 × 2x² = 6x²

+3 × -3x = -9x

2x^4 , -3x³ , 6x², -9x

In bold are the bottom two

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What is the value of 2 in 5,670,249,114? And describe 2 ways to find value?

kirill115 [55]

There are two ways in finding the place value of 2 in 5,670,249,114
First by breaking down the numbers:
5,670,249,114 = 5,000,000,000 + 600,000,000 + 70,000,000 + 200,000 + 40, 000 + 9,000 + 100 + 10 + 4 which means the Value of 2 is 200, 000<span>2. Second, by using the ones words:
5,670,249,114 = 5 billion + 6 hundred million + 70 ten million + 2 hundred thousand + 4 ten thousand + 9 thousands + 1 hundreds + 1 tens + 4 ones which means the Value of 2 is 2 hundred thousand

</span>

4 0

2 years ago

A cylinder has a height of 4 inches greater than the radius of its base. Find the radius and the height to the nearest inch if t

anastassius [24]

Answer:

$h=5in, r=1in$

Step-by-step explanation:

The volume of a cylinder is:

$V=\pi*r^2*h$

where $r$ is the radius and $h$ is the height.

The height is 4 inches greater that the radius, so:

$h=r+4in$

Substituting this in the formula for volume:

$V=\pi*r^2*(r+4)$

the volume is $V=5\pi in^3$

thus:

$5\pi in^3=\pi*r^2*(r+4in)$

Dividing everything between pi:

$5in^3=r^2*(r+4in)$

$5in^3=r^3*+4r^2$

We can see that the solution for this is $r=1in$

since $(1)^3*+4(1)^2=1+4=5$

We have the radius, now we find the height:

$h=r+4in=1in + 4in = 5in$

$h=5in, r=1in$

7 0

3 years ago

Read 2 more answers

Can anyone help me out on this question

statuscvo [17]

12/4(-1)+2=

12/-4+2 =

12/-2 =

-6

8 0

2 years ago

Read 2 more answers

Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t

Neporo4naja [7]

Answer:

$V=61.66$

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

$V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx$

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

$f(x)=g(x)\\ln(x)=\frac{1}{2}x-2$

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

$R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\$

and by replacing in the integral we have

$V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\$

$V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]$

and by evaluating in the limits we have

$V=61.66$

Hope this helps

regards

3 0

2 years ago

The level of a lake was 8 inches below normal. It decrease 1 1/4 inches in June and 2 3/8 inches more in July. What was the new

zloy xaker [14]

Answer:

Step-by-step explanation:

the initial level is below normal so it is represented by a negative number. the level continued to decrease in June and July so those changes are also represented by negative numbers. find the sum of these values to find what the new level was with respect to the normal level

write the mixed numbers as improper fractions

get common denominator

add the numerators since all the numbers are negative and have a common denominator. write the improper fraction as a mixed number

3 0

2 years ago