Answer:
The numbers are 11 and 49.
Step-by-step explanation:
<em>x = 5y - 6 </em> This is just the first sentence written as an equation.
<em>x + y = 60</em> This is just the second sentence written as an equation.
<em>5y - 6 + y = 60</em> Substitute x for what you know it is equal to
<em>6y - 6 = 60</em> Collect like terms
<em>6y = 66</em> Add 6 to each side
<em>y = 11</em> Divide each side by 6
<em>x = 5 × 11 - 6 </em> Substitute y for what you know it is
<em>x = 55 - 6</em> Simplify by working out 5 × 11 = 55
<em>x = 49</em> Subtract 6 from 55 to get 49
Answer:
3-6=3
Step-by-step explanation:
Answer:
0.45
Step-by-step explanation:
Divide 9 by 20.
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.