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3 years ago

10

Please help!!:

1 answer:

mina [271]3 years ago

8 0

1) in order for two lines to be perpendicular, their gradients must multiply together to get -1

-1/3*b=-1

b=3

5=3(3)+b

5=9+b

b=-4

equation of the line is y=3x-4

2) parallel lines have the same gradient

4=2(-3)+b

4=-6+b

b=10

equation of the line is y=2x-10

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3 years ago

If the angles of a triangle are in the ratio 3:4:2 find the value of all triangle

Nata [24]

Answer:

Step-by-step explanation:

If the ratio of triangle = 3:4:2

Total ratio = 3+4+2 = 9

The sum of angle in a triangle is 180°

1st angle= 3/9 × 180 = 2 × 20 = 60°

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3 years ago

What is the value of x?

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3 years ago

102/159 = x/4<br><br> Find X

-BARSIC- [3]

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3 years ago

Estimate the area of Alberta in square miles. Show your reasoning

ella [17]

Answer: About $278,250\ mi^2$

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid can be calcualted with the formula:

$A_t=\frac{h}{2}(B+b)$

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

$A_r=lw$

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

$A=\frac{h}{2}(B+b)+lw$

Substituting vallues, you get:

$A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2$

Therefore, the area of of Alberta is about $278,250\ mi^2$ .

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3 years ago