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ra1l [238]
3 years ago
8

A hot air balloon is acted on by two forces. One force is its weight, equal to

Physics
1 answer:
Rasek [7]3 years ago
8 0

Answer:

no change

Explanation:

The Newton's Second Law of motion states that when an unbalanced force is applied to an object, it causes an accelerated motion in the object, in the direction of the unbalanced force. So, if there is no unbalanced force, then there is no motion. In this case both the forces have same magnitude and opposite direction. Therefore, the unbalanced force will be zero:

Unbalanced Force = Upthrust - Weight

Unbalanced Force = 2448 N - 2448 N

Unbalanced Force = 0 N

hence, there will be no motion in the vertical direction. Therefore, the correct option is:

<u>no change </u>

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Two balloons are charged with an identical quantity and type of charge: -4 nc They are held apart at a separation distance of 70
blagie [28]

Answer:

29.4 uN

Explanation:

The electric force between two charges can be calculated using Coulomb's Law. According to this law the force between two point charges is given as:

F=k\frac{q_{1} q_{2} }{r^{2}}

where k is a proportionality constant known as the Coulomb's law constant. Its value is 9 \times 10^{9} Nm²/C²

r = distance between charges = 70 cm = 0.7 m

q1 = q2 = 4nC = 4 \times 10^{-9} C

The negative sign indicates that the charges are negative. In the formula we will only use the magnitude of the charges.

Using these values in the formula, we get:

F=9 \times 10^{9} \times \frac{4 \times 10^{-9} \times 4 \times 10^{-9}}{0.7^{2}}\\\\ F=2.94\times10^{-7} N\\\\ F=29.4 \times 10^{-6} N\\\\ F=29.4 \mu N

Therefore, the magnitude of repulsive force between the given charges will be 29.4 uN

8 0
4 years ago
Select the correct answer.
IgorC [24]

Answer:

D. Newton's Third Law of Motion

Explanation:

Newton's law of gravity is definitely not applicable to your hands. So we can cross this bad boy out

Newton's First Law is F=MA (force equals mass times acceleration). This is basically the root of most physics but it isn't the reason for your hand being red after hitting a wall.

Newton's Second law deals with velocities and forces, so even though you are apply a force your are not changing the velocity of the wall much.

Newton's Third Law basically says that for whatever force you apply to an object, that object will apply an equal and opposite force back to you. This is why your hand gets red. When you slap the wall with all your strength, the wall hits your hand back with the same amount of force. The 2nd law can also be seen when you're trying to push a desk and it won't budge. You are pushing on it, but the desk is pushing back. (there are multiple other factors applicable like friction but we physicists like to ignore them :) )

I hope this helps!

7 0
4 years ago
Centripetal forces are always directed toward the (center, outside) of a circle.
dexar [7]

Answer:

Centripetal forces are directed toward the center of a circle.

Hope this helps.

Explanation:

4 0
3 years ago
A new object, Object X, was discovered outside our solar system. Object X is small and rocky, is not a satellite of any other ob
hram777 [196]
<span>The characteristics of Object X most closely resemble those of other Comets. The correct option among all the options that are given in the question is the first option. The other options in the question can be negated. I hope that this is the answer that has actually come to your great help.</span>
4 0
3 years ago
Read 2 more answers
Please need help fast
iVinArrow [24]

(a) See graph in attachment

The appropriate graph to draw in this part is a graph of velocity vs time.

In this problem, we have a horse that accelerates from 0 m/s to 15 m/s in 10 s.

Assuming the acceleration of the horse is uniform, it means that the velocity (y-coordinate of the graph) must increase linearly with the time: therefore, the velocity-time graph will appear as a straight line, having the final point at

t = 10 s

v = 15 m/s

(b) 1.5 m/s^2

The average acceleration of the horse can be calculated as:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time interval

In this problem,

u = 0

v = 15 m/s

t = 10 s

Substituting,

a=\frac{15-0}{10}=1.5 m/s^2

(c) 75 m

For a uniformly accelerated motion, the distance travelled can be calculated by using the suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance travelled

u is the initial velocity

t is the time interval

a is the acceleration

In this problem,

u = 0

t = 10 s

a=1.5 m/s^2

Substituting,

s=0+\frac{1}{2}(1.5)(10)^2=75 m

(d) See attached graphs

In a uniformly accelerated motion:

- The distance travelled (x) follows the equation mentioned in part c,

x=ut+\frac{1}{2}at^2

So, we see that this has the form of a parabola: therefore, the graph x vs t will represents a parabola.

- The acceleration is constant during the motion, and its value is

a=1.5 m/s^2 (calculated in part b)

therefore, the graph acceleration vs time will show a flat line at a constant value of 1.5 m/s^2.

6 0
3 years ago
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