Based on the attached image:
- The name of the longitude line that passes through point A is the International Date Line
- The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
- The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
- Longitude 120° is B
- Solar time at Point B is 4 pm
- The location will correspond to any point on the same latitude as A
<h3>What are lines of longitude?</h3>
Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.
Longitude lines divide the earth into semi-circles.
Longitude lines are known as meridians and each meridian measures one arc degree of longitude.
Considering the attached image:
- The name of the longitude line that passes through point A is the International Date Line
- The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
- The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
- Longitude 120° is B
- Solar time at Point B is 4 pm
- the location will correspond to any point on the same latitude as A
In conclusion, longitude lines are imaginary lines and run from North to South on the earth.
Learn more about lines of longitude at: brainly.com/question/1939015
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Explanation:
The Coriolis effect happens when an entity is perceived from a moving reference frame going in a straight path. The changing reference frame makes the object appear as if it were moving along a curved road.
Circulation is counter-clockwise in the northern hemisphere. Circulation is clockwise in the southern hemisphere, and it is the equator, it is straight down without circulation.
Answer:
Explanation:
Flux through the coil = nBA , n is no of turns , B is magnetic flux and A a is area of the coli
= 200 x 5.6 x 10⁻⁵ x 11.8 x 10⁻⁴
= 13216 x 10⁻⁹ weber .
b ) When the coil becomes parallel to magnetic field , flux through it will become zero.
c ) e m f induced = change in flux / time
= 13216 x 10⁻⁹ / 4.9 x 10⁻²
= 2697.14 x 10⁻⁷ V
= 269.7 x10⁻⁶
269.7 μV.