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STALIN [3.7K]
3 years ago
5

This subject is hard enough why they have to make it harderrrrrrr-

Mathematics
2 answers:
shepuryov [24]3 years ago
7 0
Frrrrrrrrr. Mathgggg
Citrus2011 [14]3 years ago
5 0
Fr mathhhhhhhhhHhHhHhhHhhHhHhhHhHHhH
You might be interested in
4(-7)<br>show work please ​
Lostsunrise [7]

The equation is asking you to multiply.

= 4 * -7

= -28

Hope This Helped! Good Luck!

6 0
3 years ago
Read 2 more answers
Can someone help solve
leva [86]

\frac{-18z^{7}y^{5}-9z^{9}y^4+18z^6y^8}{9zy^{2} }= -2z^6y^3-z^8y^2+2z^5y^6


When variables with exponents are divided by each other, you subtract the exponents.

For example:

\frac{x^2}{x^1} = x^{2-1} =x^1

\frac{x^5}{x^3} =x^{5-3} = x^2

8 0
3 years ago
Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)
zubka84 [21]
\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } &#10;

This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

\frac{ \sqrt{-49}}{7-2i-4-9i}

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result: 

\frac{ \sqrt{-49} }{3-11i}

Now, the \sqrt{-49} must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to \sqrt{49}  \sqrt{-1}
This means that we get the result 7i for the numerator.

\frac{7i}{3-11i}

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: x^2 - y^2 =(x+y)(x-y)
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

\frac{7i (3+11i)}{(3-11i)(3+11i)}

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how (3-11i)(3+11i)= 3^2 -(11i)^2 therefore, we can finally write:

\frac{7i(3+11i)}{3^2 - (11i)^2 }

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product 7i(3+11i) = 21i+77i^2.
You should know from your classes that i^2 = -1, thefore the numerator simplifies to -77+21i
You can do it as a curious thing, but simplifying yields the result:
\frac{-77+21i}{130}
7 0
3 years ago
Multiply (-6 + i)(-2 + 9i).
malfutka [58]

Answer:

b

Step-by-step explanation:

go with that and you may win at this multiply question

4 0
3 years ago
Read 2 more answers
Find the area of the trapezoid below.
spin [16.1K]

Answer: 72 9 times 8 is 72

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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