Let's solve your equation step-by-step.<span><span>−<span>5<span>(<span>x−4</span>)</span></span></span>=<span>−<span>30
</span></span></span>Step 1: Simplify both sides of the equation.<span><span>−<span>5<span>(<span>x−4</span>)</span></span></span>=<span>−30</span></span>
<span>Simplify: (Show steps)</span><span><span><span>−<span>5x</span></span>+20</span>=<span>−<span>30
</span></span></span>Step 2: Subtract 20 from both sides.<span><span><span><span>−<span>5x</span></span>+20</span>−20</span>=<span><span>−30</span>−20</span></span><span><span>−<span>5x</span></span>=<span>−<span>50
</span></span></span>Step 3: Divide both sides by -5.<span><span><span>−<span>5x</span></span><span>−5</span></span>=<span><span>−50</span><span>−5</span></span></span><span>x=<span>10
</span></span>Answer:<span>x=<span>10</span></span>
Answer:
A
Step-by-step explanation:
The velocity of a moving body is given by the equation:
Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.
And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.
We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:
By substitution:
Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:
Zero Product Property:
Now, by testing values for t<1, 1<t<4, and t>4, we see that:
So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.
Hence, our answer is A.
The absolute value is the value of the number without the sign. So in this case it's 3 and -3
The answer is
(x+10)(x-3)
T>L+D/B
(Assume no parentheses missing and use PEMDAS rule)
Subtract L from both sides
T-L > L-L + D/B
T-L>D/B
Multiply both sides by B (assuming B>0)
B(T-L)>D/B*B
B(T-L)>D
Interchange two sides,
D<B(T-L) (if B>0)
if B<0, then D>B(T-L)
