PH I think hope this helps
Answer:
The answer to your question is X = 0.072
Explanation:
Data
X I₂ = ?
mass of I₂ = 55.6 g
mass of hexane = 245 g
Formula
X I₂ = (moles of Iodine) / (moles of iodine + moles of hexane)
Process
1.- Convert the mass of reactants to moles
atomic mass of I₂ = 2 x 127 = 254g
atomic mass of hexane = (12 x 6) + (14 x 1) = 86 g
254 g ---------------- 1 mol
55.6 g------------- x
x = (55.6 x 1)/254
x = 0.22 moles of I₂
86 g ------------- 1 mol
245 g ------------- x
x = (245 x 1)/86
x = 2.84 moles
2.- Calculate the mole fraction of I₂
X = 0.22 / (0.22 + 2.84)
X = 0.22 / 3.07
X = 0.072
We can dictate the mechanism of the reaction by looking at the exponents of the reactants in the reaction rate equation. Since [xy] has an exponent of 1, then the reaction follows the first order reaction with respect to xy. Similarly, the reaction follows the first order with respect to z₂. Then, the overall is the sum of each of their orders which is 2.
m(O2)=50g
m(H2)=50g
m(H2O)-?
n2(H2)-?
2H2 + O2 = 2H2O
n(O2)= m (O2)/M(O2) =50g / 32 g/mol= 1,56 mol.
n(H2)= m (H2)/M(H2) =50g / 2 g/mol= 25 mol.
Since oxygen gas is the limiting reactant,
n(O2)< 2 n(H2) from reaction.
n(H2O)= 2n(O2)= 2n (H2 reac.)=2*1,56 mol=3,12mol.
m(H2O)=n(H2O)*M(H2O)= 3,12mol* 18 g/mol.
n2(H2)= n(H2) - n (H2 reac.)=25mol - 3,12mol=21,88mol.
You would have started with 5 grams of reactants