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BabaBlast [244]
3 years ago
14

g How many moles of NaOH are present in a sample if it is titrated to its equivalence point with 44.02 mL of 0.0885 M H2SO4? 2Na

OH(aq) + H2SO4(aq) --> Na2SO4(aq) + 2H2O(l)
Chemistry
1 answer:
Lisa [10]3 years ago
8 0

Answer:

n_{base}=3.90x10^{-3}molNaOH

Explanation:

Hello!

In this case, since the sulfuric acid and sodium hydroxide react in a 1:2 mole ratio, given the reaction, we realize they have the following mole ratio at the equivalence point:

2*n_{acid}=n_{base}

Which in terms of concentrations and volumes is:

2*M_{acid}V_{acid}=n_{base}

Thus, we can plug in the volume and concentration of acid to find the moles of base:

n_{base}=0.04402L*0.0885\frac{mol}{L} \\\\n_{base}=3.90x10^{-3}molNaOH

Best regards!

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olchik [2.2K]

Answer:

The answer to your question is   V2 = 1.82 l

Explanation:

Data

Volume 1 = 77 l

Pressure 1 = 18 mmHg

Volume 2 = ?

Pressure 2 = 760 mmHg

Process

Use Boyle's law to solve this problem

                P1V1 = P2V2

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                 V2 = P1V1/P2

-Substitution

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-Simplification

                 V2 = 1386 / 760

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5 0
3 years ago
What types of bonds or interactions are overcome when a nonmetal extended network melts?
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Covalent bonds or interactions are overcome when a nonmetal extended network melts.

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One technique to depict the formation of covalent connections between atoms is with Lewis dot formations. The number of unpaired electrons and the number of bonds that can be formed by each element are typically identical. Each element needs to share an unpaired electron in order to establish a covalent bond.

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2 years ago
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Explanation:

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