Answer : The specific heat of tungsten is,
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of tungsten = ?
= specific heat of water =
= mass of tungsten = 19.5 g
= mass of water = 78.5 g
= final temperature =
= initial temperature of tungsten =
= initial temperature of water =
Now put all the given values in the above formula, we get
Therefore, the specific heat of tungsten is,
The answer for this problem is 22.12. Hope it helped. :)
WORK: 10.5+11.62=22.12
Do you have the molecular weight? I’ve never done this type of chemistry before but from researching it the equation is nxAx100/M. n=# of atoms, A=atomic mass, & M=molecule weight. Sorry if this isn’t helpful, if you can give me an example I may be able to help.
Answer:
The answer to your question is Qt = 15750 cal
Explanation:
Data
mass = m = 150 g
Initial temperature = T1 = 0°C
Final temperature = T2 = 25°C
Process
1.- Calculate the Latent heat of fusion
Latent heat of fusion for water = l = 80 cal/g
Heat = Q
Formula
Q = ml
Substitution
Q = (150)(80)
Simplification and result
Q = 12000 cal
2.- Calculate the Specific heat
Specific heat of water = C = 1 cal/g°C
Formula
Q = mCΔT
Substitution
Q = (150)(1)(25 - 0)
Simplification and result
Q = 3750 cal
3.- Calculate the total heat
Qt = 12000 + 3750
Qt = 15750 cal
Answer:
11.3 g.
Explanation:
Hello there!
In this case, since the combustion of butane is:
Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:
Therefore, the resulting mass of water is:
Best regards!