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2 years ago

Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)

Mathematics

1 answer:

Burka [1]2 years ago

7 0

$\large{ \boxed{ \tt{OUR \: ANSWER : \underline{ \$ \: 583.3125}}}}$

Well , You can solve this question using two ways. I'm gonna use the both ways to make you clear and the one which you can easily understand , pick up that way and start solving another question as similar as this one.

$\large{ \tt{❃ \: FIRST \: METHOD }} :$

This method is related to the unitary method. Let's start :

We're provided - Amount Kelly earns per hour for gardening = $ 12.75 and we're asked to find out the amount she earn if she worked 45.75 hours this month.

We know , Kelly probably earns more money if she worked 45.75 hours comparison to if she worked 1 hour. So You just multiply 45.75 & 12.75 , you would get $ 583.3125 and that's your final answer.

$\large{ \tt{❃ \: SECOND \: METHOD}} :$

This method is related to the proportion. If you haven't learned about it yet , use the above way to solve the similar type of questions. Let's start :

Let Kelly earns X dollars if she worked 45.75 hours this month. [ Now , See the attached picture ]

Here , we can see the time is increased which implies that money will surely be increased. Such type of proportion is called direct proportion.

Here , the ratio of time ( in hours ) = 1 : 45.75 and the ratio of amount ( in dollars ) = 12.75 : x . Now , Set up an equation and solve for x :

$\large{ \tt{ ❁ \: \frac{1}{45.75} = \frac{12.75}{x}}}$

$\large{ \tt{↦ \: 1 \times x = 45.75 \times 12.75}}$

$\large{ \tt{↦x = \$ \: 583.3125}}$

Hence , She earned $ 583.3125 .

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Write an inequality for the situaions below and solve:

musickatia [10]

Answer

Find out the how many boxes of paper can the forklift move at one time .

To proof

Let us assume that the number of boxes be x.

As given

A forklift can carry up to 2500 pounds.

You want to move boxes of paper which each weigh 140 pounds.

The paper boxes are supported on one pallet which weighs 50 pounds.

Than the equation is become in the form

140x +50 ≥ 2500

140x ≥ 2500 - 50

140x ≥ 2450

$x \geq \frac{2450}{140}$

x ≥ 17.5

Therefore the 18 boxes of paper can the forklift move at one time .

Hence proved

5 0

3 years ago

P=-3w+9 tell me the steps I already have the steps

anastassius [24]

You're solving for w for I assume.

P= -3w+9, put -3w on the left side and P on the right side.
3w= -P+9, divide both sides by 3.
w= -P+9 over 3.
w= -P over 3 plus 9 over 3.
(Final Answer):
w= -p over 3 plus 3.

Hope this helps.

4 0

3 years ago

If a man drives 600km from Johannesburg to Durban. He starts his journey with a full tank of petrol. If the man drives at an ave

arlik [135]

Answer:

I think it's 5

Step-by-step explanation:

im not sure

but correct me if I'm wrong

7 0

2 years ago

Can you help with this one?

deff fn [24]

Answer:

Step-by-step:

should be 27 too

90 degree

70 degree

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27+70 = x

97 = x

4 0

3 years ago

Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa

Alik [6]

Answer:

We conclude that the proportion of student body in favor of him is significantly less than or equal to 50%.

Step-by-step explanation:

We are given that Mike runs for the president of the student government and is interested to know whether the proportion of the student body in favor of him is significantly more than 50 percent.

A random sample of 100 students was taken. Fifty-five of them favored Mike.

Let p = proportion of the students who are in favor of Mike.

So, Null Hypothesis, $H_0$ : p $\leq$ 50% {means that the proportion of student body in favor of him is significantly less than or equal to 50%}

Alternate Hypothesis, $H_A$ : p > 50% {means that the proportion of student body in favor of him is significantly more than 50%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students body in favor of Mike = $\frac{55}{100}$ = 0.55

n = sample of students taken = 100

So, test statistics = $\frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }$

= 1.01

The value of z test statistics is 1.01.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is less than the critical value of z as 1.01 < 1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of student body in favor of him is significantly less than or equal to 50% or proportion of the students in favor of Mike is not significantly greater than 50 percent.

4 0

3 years ago