The length of a rectangle is 1 m less than twice the width, and the area of the rectangle is 21 m?. Find the dimensions of the r
1 answer:
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1. Method 1: By Listing MultiplesList out all multiples of each denominator, and find the first common one.
2: 2 , 4
4: 4
Therefore, the LCD is 4
Method 2: By Prime FactorsList all prime factors of each denominator, and find the union of these primes.
Therefore, the LCD is <span>2 x 2 = 4
</span>
2. <span>Make the denominators the same as the LCD
</span>
<span>
3. </span><span>Simplify. Denominators are now the same.
</span>
4. Join the denominators
5. <span>Simplify
</span>
<span>
Done! :) </span><span>Decimal Form: -0.25</span>
2: 2 , 4
4: 4
Therefore, the LCD is 4
Method 2: By Prime FactorsList all prime factors of each denominator, and find the union of these primes.
Therefore, the LCD is <span>2 x 2 = 4
</span>
2. <span>Make the denominators the same as the LCD
</span>
<span>
3. </span><span>Simplify. Denominators are now the same.
</span>
4. Join the denominators
5. <span>Simplify
</span>
<span>
Done! :) </span><span>Decimal Form: -0.25</span>
Answer:
-5y + 8x
Step-by-step explanation: