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3 years ago

Can someone please give the answer

Mathematics

1 answer:

guapka [62]3 years ago

5 0

Answer:

I can only answer when it is written with pencil

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Deborah hikes due south for 3 miles. She then turns due west and hikes 4 miles. What is the shortest distance between the starti

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Answer:

5 miles

Step-by-step explanation:

The two legs of Deborah's hike form the right-angle legs of a right triangle. The shortest distance is then the hypotenuse of that triangle, found using the Pythagorean theorem.

d^2 = 3^2 + 4^2 = 9 +16 = 25

d = √25 = 5

Deborah ends 5 miles from her start.

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3 years ago

Quantas diagonais partem do hexagono?

Free_Kalibri [48]

The answer would be nine

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4 years ago

Jack owns a small restaurant called Best Burgers. For one week, he collected sales data on the type of side order served with ea

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4 years ago

The volume of water and a rectangle swimming pool can be modeled by the function v(x)=x^3+13x-210. If the depth of the pool is g

S_A_V [24]

Answer:

Required,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

Step-by-step explanation:

Given volume and depth respectively,

$V(x)=x^3+13x-210$ and $x-3$

To find length and width of the rectanglular swiming pool we know,

Volume=length $\times$ height $\times$ depth.

Let depth=D=x-3, length=L, width=W, then

$V=DLW$

$x^3+13x-210= LW(x-3)$

$LW=\frac{x^3+13x-210}{x-3}$

After divide we will get $x^2-3x-22$ with remainder -144.

Thus,

$x^3+13x-210=(x^2-3x-22)(x-3)-144=(x-3)LW$

Now to find root of,

$x^2-3x-144=\frac{3\pm\sqrt{9+88}}{2}=\frac{3\pm \sqrt{37}}{2}$

Thus,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

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3 years ago

What is the minimum width of the square base?

riadik2000 [5.3K]

4 I think I might be wrong so sorry if I am wrong

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4 years ago