In 2 g H₂ there are 6,023.10²³ molecules H₂ and 2 x 6,023.10²³ atoms H
<h3>Further explanation
</h3>
The mole is the number of particles contained in a substance
1 mol = 6.02.10²³
Moles can also be determined from the amount of substance mass and its molar mass
The question is :
<em>in 2 grams of hydrogen how many molecules and how many atoms</em>
MW H₂ = 2.01568 u (2 atoms of H)
MW H = 1.00784 u
Or a simply way :
1 g of H atoms = 1 mol of H (MW H = 1 g/mol)
2 g of H atoms (in 2 gr H₂) = 2 moles of H
2 g of H₂ molecules = 1 mole of H₂ (MW H₂=2 g/mol)
so in 2 g H₂ there are 6,023.10²³ molecules H₂ and 2 x 6,023.10²³ atoms H
Answer:
Cr
Explanation:
Cr will displace Sn from compound because Cr is higher than Sn in the electrochemical series of metals
Answer:
(a).
(4 × C) + (8 × H)
= (4 × 12) + (8 × 1)
= 48+8
= 56 g
(b).
= (4 × C) + (6 × H)
= (4 × 12) + (6 × 1)
= ( 48+6 )
= 54 g
(c).
= ( 2 × Si ) + ( 4×Cl ) + (2×H)
= (2×28) + (4×35.5) + (2×1)
= 56 + 142 + 2
= 200 g
(d).
= (1×P) + (4×O) + (3×H)
= 31 + 64 + 3
= 98 g
<h2>
Answer:</h2>
390 g KNO₃
<h2>
General Formulas and Concepts:</h2><h3><u>Chemistry</u></h3>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3><u>Math</u></h3>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<h2>
Explanation:</h2>
<u>Step 1: Define</u>
2.3 × 10²⁴ formula units KNO₃
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of K - 39.10 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g.mol
Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol
<u>Step 3: Convert</u>
<u /> = 386.172 g KNO₃
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules and round.</em>
386.172 g KNO₃ ≈ 390 g KNO₃