The percent error associated with Jason’s measurement is 0.596%.
HOW TO CALCULATE PERCENTAGE ERROR:
- The percentage error of a measurement can be calculated by following the following process:
- Find the difference between the true value and the measured value of a quantity.
- Then, divide by the true value and then multiplied by 100
- The true value of the density of iron is 7.874 g/mL
- Jason observed value is 7.921 g/mL
Difference = 7.921 g/mL - 7.874 g/mL
Difference = 0.047 g/mL
Percentage error = 0.047/7.874 × 100
Percentage error = 0.596%.
Therefore, the percent error associated with Jason’s measurement is 0.596%.
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Answer:
because strong heated makes temperatures and pressures reach the substance's triple point in its phase diagram, So the substance can be in a liquid case , and that is against the sublimation process meaning
which define as the transition of a matter or a substance from the solid phase to the gas phase directly, without passing through the intermediate liquid phase
sublimation process happens by absorbing of heat which makes molecules overcome attractive force between each other and changing to gas phase
but in the previous case it will pass through the liquid phase so it will not be sublimation process any more
Mass number = protons + neutrons
mass number = 5 + 7
mass number = 12
<u>Answer:</u> The net ionic equation for the given reaction is 
<u>Explanation:</u>
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are the ions which do not get involved in a chemical equation. It is also defined as the ions that are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of hydrochloric acid and potassium sulfite is given as:

Ionic form of the above equation follows:

As, potassium and chloride ions are present on both the sides of the reaction, thus, it will not be present in the net ionic equation.
The net ionic equation for the above reaction follows:

Hence, the net ionic equation for the given reaction is written above.