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emmasim [6.3K]
2 years ago
7

Which chemical element has the shortest name?

Chemistry
2 answers:
larisa86 [58]2 years ago
5 0
Tin would be the right answer
frutty [35]2 years ago
3 0

Answer:

Tin

Explanation:

Tin is the chemical element which has the shortest name. It is a metallic element with the chemical symbol Sn which comes from the latin word stannum.

hope this helps!! :) :) :) (please give me brainliest!!)

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1. The equation for the reaction between zinc and aqueous copper(II) sulfate is shown.
Fed [463]

Answer:

The oxidation state of the reducing agent has changed from 0 to +2.

Explanation:

reducing agent is anything that loses electron or gains oxygen

in this case, zinc

3 0
3 years ago
Select 2-possible ointment bases. Select one or more:
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Answer:

The correct option is: c. petroleum jelly, d. Polyethylene glycol 4000/600 mixture                

Explanation:

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An ointment base medication gets rapidly absorbed into the skin. Some of the examples of <u>ointment bases</u> include water-soluble bases: <u>polyethylene glycol</u>, hydrocarbon bases: <u>petroleum jelly</u>, paraffin wax.

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2 years ago
Based on the following chemical equation how many hydrogen atoms are present in the products side?
e-lub [12.9K]

Answer:

the answer is 6

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8 0
2 years ago
how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate
Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})

= 95.7gNaClO_3

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate  and then the grams are converted to kg.

95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

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3 years ago
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