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3 years ago

I'll give you brainiest please help me.

2 answers:

6 0

Being involved in extracurricular activities can help you stand out on your college applications because it shows that you are skilled in more than 1 thing. Depending on the extracurricular you’re taking, you could be very good at strategic and critical thinking. This could be helpful in your future. Colleges do what the best of the best. Being involved in extracurricular activities also can show that you can take on more than 1 task. A lot of people can’t multitask or have a short attention span. This could be really good.

2. If I could create my own club or organization it would be one that explores individuals talents. Not a lot of people are sure what they want to be when they get older and I’d like to help them with that. Not any skills to be exact. The requirements would be to be serious about this, having manners, self-control, bring able to know what to respond to and what not, getting help instead of taking things into their own hands, and good listening.

3. Yes. You could use my first response as the answer to this question. There’s too many reason why getting into extracurricular activities is beneficial to getting the career of your dreams.9

IRISSAK [1]3 years ago

3 0

Yoooo I’m bored lol hehehe

You might be interested in

Paul Springer plans to save for a down payment for a house in 10 years. He will be able to invest $12,000 today in a money marke

Bad White [126]

Answer:

The correct answer is $20,772.92.

Explanation:

According to the scenario, the given data are as follows:

Payment (pmt) = $12,000

Rate of interest = 5.50%

Rate of interest per month (r) = 5.50 / 12 months = 0.46%

Time = 10 years (n) = 120 months

So, the future value can be calculated by using following formula:

Future value = PMT ×(1+r)^n

= $12,000 × ( 1 + 0.46% )^120

= $20,772.92

Hence, the future value at the end of 10 years will be $20,772.92.

8 0

3 years ago

Trew Company plans to issue bonds with a face value of $902,000 and a coupon rate of 6 percent. The bonds will mature in 10 year

Agata [3.3K]

Answer:

$807,992

Explanation:

issue $902,000 with a 6% semiannual coupon and 10 year maturity. coupon payment = $27,060

if the annual market interest rate = 7.5%, the bonds should be sold at a discount:

issue price = present value of face value + present value of interest payments

present value of face value = $902,000 / (1 + 3.75%)²⁰ = $431,961
present value of annuity = $27,060 x {1 - [1 / (1 + 3.75%)²⁰]} / 3.75% = $376,031

issue price = $431,961 + $376,031 = $807,992

the journal entry should be:

Dr Cash 807,992

Dr Discount on bonds payable 94,008

Cr Bonds payable 902,000

5 0

3 years ago

Which of the following is not a good example of a substitute product that triggers stronger competitive pressures? A. video-on-d

Paha777 [63]

Answer:

The correct solution to either the following question seems to be Option E (Coca-Cola as a substitute for Pepsi ).

Explanation:

A substitute product seems to be a product of some other sector that offers integrated values to the customer as the commodity manufactured by organizations in the same organization.
These goods are alternatives because they meet identical market requirements and have substantial demand elasticity. Of example, the price of Pepsi seems to have a strong connection with the market of Coke.

Other possibilities aren't related to something like the scenario in question. And the latter reaction is the correct one.

4 0

4 years ago

You own a stock portfolio invested 34 percent in Stock Q, 18 percent in Stock R, 36 percent in Stock S, and 12 percent in Stock

Step2247 [10]

Answer:

Portfolio beta = 1.3156

Explanation:

The portfolio beta is a function of the weighted average of the individual stocks betas' that form up the portfolio. To calculate the portfolio beta, we use the following formula,

Portfolio beta = wA * Beta of A + wB * Beta of B + ... + wN * Beta of N

Where,

w represents the weight of each stock in portfolio

Portfolio beta = 0.34 * 1.03 + 0.18 * 1.09 + 0.36 * 1.49 + 0.12 * 1.94

Portfolio beta = 1.3156

4 0

4 years ago

The probability that a randomly selected education major received a starting salary offer greater than $52,350 is . The probabil

AveGali [126]

Answer:

1. 0.0808

2. 0.5371

3. 58.2%

Explanation:

The first part of the question, with the input data, is missing.

This is missing part:

Assume that X, the starting salary offer for education majors, is normally distributed with a mean of $46,292 and a standard deviation of $4,320

<h2>Solution</h2><h2 />

Question 1: The probability that a randomly selected education major received a starting salary offer greater than $52,350 is ________

Find the Z-score.

The Z-score is the standardized value of the random variable and represents the number of standard deviations the value of the random variable is away from the mean:

$Z-score=\dfrac{X-\mu}{\sigma}$

$Z-score=\dfrac{\$52,350-\$46,292}{\$4,320}=1.40$

$P(X>\$52,350)=P(Z>1.40)=P(Z$

The standard normal distribution tables give the cumulative probabilities as the cumulative area under the bell-shaped curve. P(Z>1.40) is the area under the curve that is to the right of Z = 1.40 or, what is the same, P(Z<-1.40) is the area to the left of Z = - 1.40.

Using the former, the table indicates P(Z>1.40) = 0.0808, which is 8.08%

Question 2: The probability that a randomly selected education major received a starting salary offer between $45,000 and $52,350 is _______.

Now you must find the area under the curve between the two Z-scores.

$Z(X=$45,000)=\dfrac{\$45,000-\$46,292}{\$4,320}=-0.30$

$Z(X=$52,350)=\dfrac{\$52,350-\$46,292}{\$4,320}=1.40$

Then, you must find the area between Z = -0.30 and Z = 1.40

That is P(Z<1.40) - P(Z < - 0.30) = P(Z > - 1.40) - P(Z < - 0.30)

= 1 - P(Z< -1.40) - P( Z < -0.30)

Now, you can work with the area under the curve to the left of Z = - 1.40 and to the left of Z = - 0.30.

From the corresponding table, that is: 1 - 0.0808 - 0.3821 = 0.5371

Question 3. What percentage of education majors received a starting offer between $38,500 and $45,000?

For X = $38,500:

$Z=\dfrac{\$38,500-\$46,292}{\$4,320}=-1.80$

For X = $45,000

Z = -0.3 (calculated above)

Then, you must find the area under the curve to the right of Z = - 1.80 and to the left of Z = - 0.3

P (Z > - 1.80) - P (Z < - 0.3)

1 - P (Z < - 1.80) - P (Z < - 0.3)

1 - 0.0359 - 0.3821 = 0.582 = 58.2%

5 0

3 years ago