The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
<h3>What is force?</h3>
The force is an action of push or pull which makes a body to move or stop.
Given is the weight of tourist W = 805 N and L is the length of the bridge.
Let the reaction force at both the ends of the bridge is R1 and R2.
Taking the moments about point A,
R1 x 0 - W x L/4 +R2 x L =0
R2 = W/4
R2 = 805 /4
R2 = 201.25 N
Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
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<span>When the difference between two results is larger than the estimates error, the result is</span>
Force = mass * acceleration. Therefore, given the force of 120 N and the mass of 46 kg:
120 N = 46 kg * acceleration
120 kg-m/s^2 = 46 kg * acceleration (in m/s^2)
acceleration = 120/46 = 2.61 m/s^2
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