It takes 300 newtons of force and a distance of 20 meters for a moving car to come to stop

Which of these is most likely consequence of failing petroleum prices

melisa1 [442]

More sales of traditional, large cars are the most likely consequence of falling petroleum prices.

<h3>Explanation</h3>

Since the majority of conventional, large cars employ combustion engines, these engines need petroleum fuel to operate.

As a result, <em>Choice C—more sales of conventional, large cars</em>—is one of the effects of dropping oil prices that is most likely to occur.

Learn more about petroleum here brainly.com/question/21518946

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7 0

2 years ago

In which way are the cathode rays deflected in the x-plates of the Cathode Ray Oscilloscope

MrRissso [65]

Answer:

The cathode ray is deflected vertically to the fluorescent screen

Explanation:

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4 0

3 years ago

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Elect the correct answer. Two identical projectiles, A and B, are launched with the same initial velocity, but the angle of laun

allsm [11]

Answer:

A. The range of A and B are equal.

Explanation:

Let u be the initial speed of both the projectile.

The gravitational force acting in the projectile is in the downward direction, sp the speed of the projectile in the horizontal direction remains constant and equals to the initial horizontal speed.

For projectile, a projectile having initial velocity u at an angle \theta with the horizontal direction,

The speed in the horizontal direction $= u\cos\theta$

and the speed in the vertical direction is $= u\sin\theta$ upward.

For A:

The speed in the horizontal direction $= u\cos75^{\circ}$

and the speed in the vertical direction is $= u\sin75^{\circ}$ upward.

For B:

The speed in the horizontal direction $= u\cos15^{\circ}$

and the speed in the vertical direction is $= u\sin15^{\circ}$ upward.

Let $t_A$ and $t_B$ are the time of flight for projectile A and B respectively.

As the range is the horizontal distance traveled by the projectile, so

The range for the projectile A $= u\cos75^{\circ}\times t_A\cdots(i)$

The range for the projectile B = $u\cos15^{\circ}\times t_B\cdots(ii)$

At the highest point, the vertical velocity is 0.

Bu using the equation of motion $v^2=u^2 +2a s.$

Here, the final velocity v=0, the initial velocity $u = u \sin \theta$ , h= vertical distance up to the highest point, and $a= -g$ (as per sign convention).

So, $s= \frac{u^2\sin^2 \theta}{2g}$

For projectile A: The maximum height attained.

$s_A= \frac{u^2\sin^2 75^{\circ}}{2g}$

For projectile B: The maximum height attained.

$s_B= \frac{u^2\sin^2 15^{\circ}}{2g}$

As $\sin^2 75^{\circ} > \sin^2 15^{\circ}$ , the height of A is attained by A is more than the heigHt attained by B.

Now, the times required to reach the highest point from the ground and again form the highest point to the ground are the same.

So, the total time of flight = 2 x (Time to reach the highest point)

In a similar way, by using the equation of motion v=u+at,

The time to reach the highest point $=\frac {u\sin\theta}{g}$

where g is the acceleration due to gravity.

So, the total time of flight

$= 2 \times \frac {u\sin\theta}{g}$

The total time of flight for A

$=2 \times \frac {u\sin75^{\circ}}{g}$

The total time of flight for A

$=2 \times \frac {u\sin15^{\circ}}{g}$

Now, from equations (i) and (ii),

The range for the projectile A =

$u\cos75^{\circ}\times \frac {2u\sin75^{\circ}}{g}=\frac {u^2 \sin 150^{\circ}}{g}= \frac {u^2 \sin 30^{\circ}}{g}$

The range for the projectile B =

$u\cos15^{\circ}\times \frac {2u\sin15^{\circ}}{g}=\frac {u^2 \sin 30^{\circ}}{g}.$

Both the projectile have the same range.

Hence, option (A) is correct.

7 0

3 years ago

A satellite is placed in a geosynchronous orbit. In this equatorial orbit with a period of 24 hours, the satellite hovers over o

Mrac [35]

Answer:

see that the correct one is D

Explanation:

In this problem the satellite is subjected to the universal force of attraction

F = G M m / r²

using Newton's second law with centripetal acceleration you can find the angular velocity of the satellite

F = m a

F = m w² r

G M / r³ = w²

and w = 2π / T

In this case, the satellite is in a two-dimensional movement, where the free fall of the satellite is compensated by the horizontal displacement, for which it is always at a distance from the earth, remaining at the same point.

When reviewing the different statements we see that the correct one isD

7 0

3 years ago

A substance that produces hydrogen ions in solution is

jeka94

Answer:

vejebrv

Explanation:

what is the name in fortnite for the best first to get xp ijeie3j2bneyeeg4ggb4hbb44bb4nn3n3jekeieikkkkkijfurnrhrhhehnrrnjrhhhrri48488hrh4hh4hhe4h44h4h4hu44i4i

7 0

3 years ago

Read 2 more answers