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2 years ago

How would you use one of Newton’s laws to build a fast car?

2 answers:

5 0

The second law when a force is applied to a car the change in motion is proportional to the force divided in the mass of the car as long as expressed by the famous equation F equals MA we’re F is for stem is the mass of the car and a is the acceleration a change in the motion of the car

kodGreya [7K]2 years ago

3 0

Answer:

The second law: When a force is applied to a car, the change in motion is proportional to the force divided by the mass of the car. This law is expressed by the famous equation F = ma, where F is a force, m is the mass of the car, and a is the acceleration, or change in motion, of the car.

Explanation:

Hope this helps

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A 59.31 kg rock is sitting at the top of a cliff that is 300 m tall. What is the gravitational potential energy of that rock?

Diano4ka-milaya [45]

Answer:

The gravitational potential energy of that rock is 174371.4 J.

Explanation:

Given

Mass m = 59.31 kg

Height h = 300 m

To determine

We need to find the gravitational potential energy of the rock

We know that the potential energy of a body is termed as the stored energy due to its position.

One kind of energy comes from Earth's gravity — Gravitational potential energy (GPE).

Gravitational potential energy (GPE) can be determined using the formula

$GPE = mgh$

where

$m$ is the mass

$g$ is the gravitational acceleration which is equal to g = 9.8 m/s²

$h$ is the height

GPE is the Gravitational potential energy

now substituting m = 59.31, h = 300 and g = 9.8

$GPE = mgh$

$=59.31\times 9.8\times 300$

$=174371.4$ J

Therefore, the gravitational potential energy of that rock is 174371.4 J.

4 0

2 years ago

Under steady state, a compressor is used to increase the pressure of an ideal gas air from 100 kPa to 1 MPa. Meanwhile the tempe

Art [367]

Answer:

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Explanation:

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4 0

2 years ago

Salt is dissolved in a flask of tap water. Distilling the mixture causes the salt to separate from the water. Which type of ener

Igoryamba

Distillation, for the water to be seperated it must be heated to break the chemical bond.

8 0

2 years ago

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Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$x$ is the horizontal distance traveled by the venom

$V_{o}=3.10 m/s$ is the venom's initial speed

$\theta=47\°$ is the angle

$t$ is the time since the venom is spitted until it hits the ground

y-component:

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.44 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

$0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}$ (3)

Rewritting (3):

$-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0$ (4)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (5)

Where:

$a=-4.9 m/s^{2$

$b=2.267 m/s$

$c=0.44 m$

Substituting the known values:

$t=\frac{-2.267 \pm \sqrt{2.267^{2}-4(-4.9)(0.44)}}{2(-4.9)}$ (6)

Solving (6) we find the positive result is:

$t=0.609 s$ (7)

Substituting (7) in (1):

$x=(3.10 m/s)cos(47\°)(0.609 s)$ (8)

We finally find the horizontal distance traveled by the venom:

$x=1.289 m$

7 0

2 years ago

A blackbody curve relates _____. intensity of radiation to energy intensity of radiation to wavelength wavelength to energy surf

neonofarm [45]

A blackbody curve represents the relation between intensity of radiation with wavelength.

Here in this curve we can see that all ideal blackbody radiates almost all wavelength of radiations and these radiations are of different intensity.

here intensity will be maximum for a given wavelength of radiation and the relation of this wavelength with the temperature of the object is given by Wein's law

It is given by

$\lambda = \frac{b}{T}$

now if we increase the temperature the maximum intensity for which wavelength is given will shift to the left.

Using this all we can also compare the temperature of two blackbody for which radiation graph is given to us.

5 0

2 years ago

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