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-Dominant- [34]
2 years ago
10

Ivan's chocolate bar is 64% cocoa. If the weight of the chocolate bar is 68 grams, how many grams of cocoa does it contain? Roun

d your answer to the nearest tenth.
Mathematics
2 answers:
ankoles [38]2 years ago
7 0

Answer:

43.5 grams

Step-by-step explanation:

multiply 68 x 64%

change 64% to a decimal by moving the decimal two places left. 0.64

68 x 0.64 = 43.52 grams

Gennadij [26K]2 years ago
6 0

Answer:

0.64 x 68 = 43.5 grams

Step-by-step explanation:

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Haley had 2 blue marbles, 2 red marbles, and 4 green marbles. She gave 1 4 of her marbles to Amy and 2 4 of her marbles to Sue.
Umnica [9.8K]
The amount is 6.
Hope you have a nice day.

7 0
3 years ago
A number greater than -5
Serggg [28]

Answer:

Hi there!

Your answers are:

1) x> 5

Some numbers that would fit this equation are 6, 7, 8, etc!

2) x<= 30

Some numbers that would fit this are 30, 29, 28, etc!

3) x>= 17

Some numbers that would fit this equation are 17, 18, 19, etc!

4) x>= 90

Some numbers that would fit this are 90, 91, 92, etc!

Hope this helps!

5 0
3 years ago
If b/a=c/b=d/c=2/3, find the value of a:b:c:d
leva [86]

Answer:

the ratio would be 6.75:4.5:3:2

Step-by-step explanation:

replace d and c with

d=2 and c=3

Then using proportion multiplication, you will find that b is 4.5

now replace all b with 4.5.

Then again using proportion multiplication, you will get a is 6.75.

Plug in a, b, c, d in the ratio and you get 6.75:4.5:3:2

5 0
2 years ago
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
2z + 4x + 9y -y + 3
kotegsom [21]

Answer:

Step-by-step explanation:

2z+4x+9y-y+3

2z+4x+8y+3

=2z+4x+8y+3

8 0
3 years ago
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