Ask question

Ask question

All categories

3 years ago

14

19. Students at a certain school can enroll in one elective course: painting, theater, choir, or band. This two-way frequency

1 answer:

san4es73 [151]3 years ago

5 0

Answer:

19.0%

Step-by-step explanation:

The probability that a student in the sample data is enrolled in painting Given that the student is female is a conditional probability and can be defined as :

Let,

F = Female ; P = painting

P(Painting Given female) = P(P|F) = (PnF) / F

From the table :

(PnF) = 16

F = 84

Hence,

P(P|F) = 16 / 84 = 0.19047 = 0.19047 * 100%

P(P|F) = 19.0%

You might be interested in

a car starts at a position of -153m and undergoes a displacement of 512m. What is it's final position

notsponge [240]

Answer:

Step-by-step explanation:

There are 2 answers.

He could go further negative which means -153 - 512 = - 665

He could go towards the plus direction which is -153 + 512 = 359 which is plus.

3 0

3 years ago

While in europe if you drive 117 kim per day, how much money would you spend on gas in one week if gas costs?

LiRa [457]

What does gas cost answer then I will give you the answer

8 0

4 years ago

Add -4 + 2\3. Please answer This is apart of my grade

Sholpan [36]

Answer:

3/3

Step-by-step explanation:

-4 + 2/3 eqeuls that because well actaully there is no right answer just that's as close as u can get too a right answer

8 0

3 years ago

Help asap! pls pls i will mark brailiest

dlinn [17]

It’s the 2nd one

Sisjsjjd

8 0

3 years ago

Read 2 more answers

Find all points on the curve that have the given slope.x = 2cost, y= 8sint, slope =-1

tatuchka [14]

Answer:

$t_{1} = 0.422\pi \pm \pi\cdot i$ , $\forall \,i \in \mathbb{N}_{O}$

$t_{2} = 1.422\pi \pm \pi\cdot i$ , $\forall \,i \in \mathbb{N}_{O}$

Step-by-step explanation:

In the case of parametric equations, the slope of the curve is equal to:

$\frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

Where $\frac{dx}{dt}$ and $\frac{dy}{dt}$ are the first derivatives of $x$ and $y$ regarding $t$ . Let be $x(t) =2\cdot \cos t$ and $y(t) = 8\cdot \sin t$ , their first derivatives are found:

$\frac{dx}{dt} = -2\cdot \sin t$ and $\frac{dy}{dt} = 8\cdot \cos t$

Thus, equation for the slope is:

$\frac{dy}{dx} = -\frac{8\cdot \cos t}{2\cdot \sin t}$

$\frac{dy}{dx} = -\frac{4}{\tan t}$

If $\frac{dy}{dx} = -1$ , then:

$-1 = -\frac{4}{\tan t}$

$\tan t = 4$

Tangent is positive at 1st quadrant and is a function with a periodicity of $\pi$ , the set of solutions are:

$t_{1} = 0.422\pi \pm \pi\cdot i$ , $\forall \,i \in \mathbb{N}_{O}$

$t_{2} = 1.422\pi \pm \pi\cdot i$ , $\forall \,i \in \mathbb{N}_{O}$

7 0

3 years ago