PLEASE HELP MEEEEE!! WILL MARK BRAINLIST!!

What is the speaker’s viewWhen I heard the learn'd astronomer;

Phantasy [73]

A. He feels tired and sick because the focus on the mechanical measurements of stars is not satisfying to him.<span>
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4 0

3 years ago

The cost in dollars of making x items is given by the function C(x)=10x+900 .

Stella [2.4K]

For the given cost equation we have:

a) Fixed cost is $900.

b) For making 25 items the cost is $1150.

c) D: x ∈ [0, 150]

R: c ∈ [900, 2400]

<h3>Working with the cost equation.</h3>

Here we know that the cost equation is:

c(x) = 10*x + 900.

First, we want to get the fixed cost, it is given by evaluating the function in x = 0.

c(0) = 10*0 + 900 = 900

The fixed cost is 900.

b) Now we want to get the cost for making 25 items, to get this, we just evaluate in x = 25.

c(25) = 10*25 + 900 = 250 + 900 = 1150

c) Now, if the maximum cost is 2400, then the maximum number of items that we can make is x₀, such that:

c( x₀) = 2400 = 10*x₀ + 900

Solving for x₀ we get:

x₀ = (2400 - 900)/10 = 150

Now we want to get the range and domain.

We know that we can make between 0 and 150 items, so the domain is:

D: x ∈ [0, 150]

For the range, we know that the fixed cost for 0 items is 900, and the maximum cost is 2400, then the range is:

R: c ∈ [900, 2400]

If you want to learn more about domain and range:

brainly.com/question/10197594

#SPJ1

5 0

2 years ago

Difference between mafic intermediate and felsic magmas

Inga [223]

Both are indicators of the chemical composition of silicate minerals, magmas and rocks.

Mafic is used for silicate minerals, magmas and rocks that are composed of heavier elements, like magnesium, iron, calcium and sodium. They are dark and have high specific gravities.

<span>Opposite to the this, felsic silicate minerals, magmas and rocks in their composition have less from these heavy elements. They are composed from silicon, oxygen, aluminium and potassium, are light in color and have lower specific gravities.</span>

8 0

3 years ago

HELP PRECALC DO NOT UNDERSTAND WILL GIVE BRAINLIEST

Olegator [25]

Answer:

the lower right matrix is the third correct choice

Step-by-step explanation:

Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).

Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.

__

We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.

The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...

$\left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]$

Already, we see that the second row matches that in the lower right matrix.

The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.

The correct choices here are the two you have selected, and <em>the lower right matrix</em>.

3 0

3 years ago

Please help with this problem. It's very confusing.

Eddi Din [679]

Answer:

9x

Step-by-step explanation:

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8 0

3 years ago